Air refrigeration cycles: An air refrigerator (as used in aircraft) operates on which idealized cycle?

Difficulty: Easy

Correct Answer: Bell–Coleman (reversed Brayton) cycle

Explanation:


Introduction / Context:
Aircraft air-cycle machines and simple air refrigerators use the working fluid (air) directly. Their thermodynamic model is the Bell–Coleman or reversed Brayton cycle, not the vapour-compression cycle used with refrigerants like ammonia or R-134a.



Given Data / Assumptions:

  • Working fluid is air (treated as an ideal gas).
  • Processes are ideally isentropic compression/expansion with heat exchange at constant pressure.
  • Engine bleed air or ram air often serves as the heat source/sink.


Concept / Approach:
The Bell–Coleman cycle consists of two isentropic processes (compression and expansion in a turbine) and two constant-pressure heat transfer processes (cooling after compression and heating after expansion), producing refrigeration by expansion work.



Step-by-Step Solution:

List the ideal steps: 1–2 isentropic compression; 2–3 constant-pressure heat rejection; 3–4 isentropic expansion; 4–1 constant-pressure heat absorption (refrigeration).Cooling effect occurs during 4–1 as cold air absorbs heat from the space.This directly matches the reversed Brayton layout.Hence, the correct cycle is Bell–Coleman.


Verification / Alternative check:
Temperature–entropy diagrams and p–h surrogates for air show the characteristic Brayton rectangles/curves, not the dome typical of vapour systems.



Why Other Options Are Wrong:

  • Reversed Carnot is the theoretical upper limit, but not the practical air-cycle model.
  • “Both” is incorrect because the standard air refrigerator is specifically the reversed Brayton.
  • Reversed Rankine applies to vapour-compression, not air-cycle machines.


Common Pitfalls:
Confusing “reversed” with “Carnot” generically; always map processes to the actual hardware (compressor, cooler, turbine, heat exchanger).



Final Answer:
Bell–Coleman (reversed Brayton) cycle

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