Ages (linear relation with total): A is two years older than B, and B is twice as old as C. If A + B + C = 27, find B's present age.

Difficulty: Easy

Correct Answer: 10

Explanation:

Introduction / Context:Linear relations among three ages combined with a total allow quick variable substitution. This problem is a straightforward arithmetic exercise intended to reinforce systematic setup and solution.

Given Data / Assumptions:

  • A = B + 2.
  • B = 2C.
  • A + B + C = 27.

Concept / Approach:Eliminate A and B in favor of C (or any single variable). Solve for C from the sum, then compute B directly from B = 2C.

Step-by-Step Solution:

Substitute into total: (B + 2) + B + C = 27. With B = 2C ⇒ (2C + 2) + 2C + C = 27 ⇒ 5C + 2 = 27 ⇒ C = 5. Hence B = 2C = 10; A = B + 2 = 12.

Verification / Alternative check:Sum 12 + 10 + 5 = 27 (✓); relations A = B + 2 and B = 2C both hold (✓).

Why Other Options Are Wrong:They correspond to incorrect solutions for C that do not satisfy the total or the given relations.

Common Pitfalls:Adding instead of substituting, or mixing which person is twice as old as whom, which flips the relation.

Final Answer:10

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