Age order logic – Rajnish is older than Rajesh and Raman. Ramesh is older than Rajesh but younger than Rajeev. Raman is older than Rajeev. Who is the oldest among them?

Introduction / Context:This is a partial-order reasoning task: consolidate pairwise comparisons into a single consistent ranking to identify the maximum (oldest) element.

Given Data / Assumptions:

• Rajnish > Rajesh; Rajnish > Raman.
• Ramesh > Rajesh and Rajeev > Ramesh.
• Raman > Rajeev.

Concept / Approach:From Rajeev > Ramesh and Ramesh > Rajesh, we have Rajeev > Ramesh > Rajesh. From Raman > Rajeev, we have Raman > Rajeev > Ramesh > Rajesh. Since Rajnish is older than both Rajesh and Raman, he must be older than everyone in that chain.

Step-by-Step Solution:Chain 1: Rajeev > Ramesh > Rajesh.Chain 2: Raman > Rajeev.Combine: Raman > Rajeev > Ramesh > Rajesh.Given: Rajnish > Raman and Rajnish > Rajesh.Therefore: Rajnish is older than all others.

Verification / Alternative check:No contradiction arises by placing Rajnish at the top, and all inequalities remain satisfied.

Why Other Options Are Wrong:Each of Rajeev/Ramesh/Rajesh/Raman is strictly younger than someone else (ultimately younger than Rajnish), so none can be the oldest.

Common Pitfalls:Missing the transitive implication from multiple pairwise comparisons; misreading “older than” directions.

Final Answer:Rajnish