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In a Δ ABC, the sides AB and AC are produced to P and Q respectively. The bisectors of ∠ OBC and ∠ QCB intersect at a point O. Then ∠ BOC is equal to:

90 ° + 1 ∠A 2
90 ° - 1 ∠A 2
120° + 1 ∠A 2
120° - 1 ∠A 2

Correct Answer: 90 ° - 1 ∠A 2

Explanation:

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