Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
Many embedded applications need decimal arithmetic for displays or human interfaces. The 8051 includes the DA A instruction to facilitate packed BCD operations after binary addition, ensuring the accumulator holds a valid BCD result.
Given Data / Assumptions:
Concept / Approach:
BCD correction adjusts the lower and/or upper nibble if they exceed 9 or if AC/C indicate a carry out of a nibble. The DA A instruction adds 6 to the lower nibble if needed, and conditionally adds 6 to the upper nibble, producing a valid packed BCD result in A and an updated carry if the adjusted value exceeds 99 decimal.
Step-by-Step Solution:
Verification / Alternative check:
Work an example: 49 (0x49) + 58 (0x58) = 0xA1 (invalid BCD). DA A transforms 0xA1 into 0x07 with carry set, representing 107 decimal as a packed BCD across carry and A.
Why Other Options Are Wrong:
Common Pitfalls:
Forgetting to use ADDC when adding multi-byte BCD; applying DA A to pure binary arithmetic; misunderstanding that DA A relies on AC/C and current nibble values.
Final Answer:
Correct
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