8051 instruction “DA A” (Decimal Adjust Accumulator): “In an 8051 program, the instruction DA A adjusts the accumulator after addition so that the result becomes a valid packed BCD value.” Decide if this is correct.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Many embedded applications need decimal arithmetic for displays or human interfaces. The 8051 includes the DA A instruction to facilitate packed BCD operations after binary addition, ensuring the accumulator holds a valid BCD result.


Given Data / Assumptions:

  • Packed BCD format: two decimal digits per byte (nibbles 0–9).
  • DA A is applied after ADD/ADDC on BCD operands.
  • Auxiliary carry (AC) and carry (C) flags affect the correction.


Concept / Approach:
BCD correction adjusts the lower and/or upper nibble if they exceed 9 or if AC/C indicate a carry out of a nibble. The DA A instruction adds 6 to the lower nibble if needed, and conditionally adds 6 to the upper nibble, producing a valid packed BCD result in A and an updated carry if the adjusted value exceeds 99 decimal.


Step-by-Step Solution:

Perform ADD/ADDC on BCD digits stored in A and another register.Check AC/C flags and nibble values.Execute DA A: hardware adds 0x06 to low nibble if low > 9 or AC=1.If high nibble > 9 after first step or C=1, it adds 0x60 to correct the high nibble.


Verification / Alternative check:
Work an example: 49 (0x49) + 58 (0x58) = 0xA1 (invalid BCD). DA A transforms 0xA1 into 0x07 with carry set, representing 107 decimal as a packed BCD across carry and A.


Why Other Options Are Wrong:

  • Incorrect: DA A is explicitly defined for BCD adjustment after addition.
  • Only after subtraction / ASCII: DA A is not intended for subtraction or ASCII-coded arithmetic; different techniques are used there.


Common Pitfalls:
Forgetting to use ADDC when adding multi-byte BCD; applying DA A to pure binary arithmetic; misunderstanding that DA A relies on AC/C and current nibble values.


Final Answer:
Correct

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