Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction:
The representable range in two’s-complement depends on word width. For 8 bits, the classic range is −128 to +127. This question focuses on the negative side of the range and whether stating “−1 to −128” (reverse ordering) is still a correct characterization of the set of negative values.
Given Data / Assumptions:
Concept / Approach:
In two’s-complement, the most negative number is −2^(n−1) and the most positive is +2^(n−1) − 1. For n = 8, negatives are {−128, −127, …, −1}. Writing the set as “−1 to −128” reverses the usual order but references the same elements. Thus, as a truth-value statement about which numbers are negative in 8-bit two’s-complement, it is correct.
Step-by-Step Solution:
Verification / Alternative check:
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Discussion & Comments