Solve for the missing radicand — In the equation 392 / sqrt(x) = 28, determine the value of x. Show each manipulation of the equation clearly.

Difficulty: Easy

Correct Answer: 196

Explanation:


Introduction / Context:
This question checks your fluency with algebraic manipulation involving square roots and simple fractions. The structure 392 / sqrt(x) = 28 invites you to isolate the radical term and then square appropriately to solve for x without introducing extraneous solutions.


Given Data / Assumptions:

  • Equation: 392 / sqrt(x) = 28.
  • sqrt(x) denotes the principal (non-negative) square root.
  • x is positive so that sqrt(x) is defined in real numbers.


Concept / Approach:
Isolate sqrt(x) by multiplying both sides by sqrt(x) and dividing by 28, or equivalently by cross-multiplication. Once sqrt(x) is expressed as a number, square both sides to remove the radical and obtain x. Always verify by substituting back into the original equation to avoid sign or arithmetic slips.


Step-by-Step Solution:
Start with 392 / sqrt(x) = 28.Rearrange: sqrt(x) = 392 / 28.Compute 392 / 28 = 14.Square both sides: x = 14^2 = 196.


Verification / Alternative check:
Substitute x = 196: sqrt(196) = 14, and 392 / 14 = 28. The original equation is satisfied exactly, confirming the solution.


Why Other Options Are Wrong:

  • 144: Would imply sqrt(x) = 12, giving 392 / 12 = 32.666..., not 28.
  • 24 / 48: These are not valid values of x in this context; they would make sqrt(x) non-integer and yield a non-28 quotient.
  • 784: sqrt(784) = 28 ⇒ 392 / 28 = 14, not 28.


Common Pitfalls:
Squaring the entire original fraction prematurely; inverting 392/28 incorrectly; forgetting that sqrt(x) must be non-negative in the real-number context.


Final Answer:
196

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