DC bias on capacitors: a 330 pF and a 220 pF capacitor are each connected across a 6 V DC source. What voltage appears across the 330 pF capacitor?

Introduction / Context:
When a single ideal capacitor is connected directly across a DC source, its terminal voltage equals the source voltage regardless of its capacitance value. This is fundamental for biasing circuits and decoupling planning.

Given Data / Assumptions:

• Two separate capacitors, each independently connected to a 6 V DC source.
• Ideal components; no series resistance and no initial charge differences matter in steady state.

Concept / Approach:
In steady state DC, the capacitor behaves as an open circuit but its voltage equals the source voltage to which it is connected. The capacitance value only affects charging transient time and stored charge (Q = C * V), not the final steady-state voltage when connected directly across the source.

Step-by-Step Solution:

Verification / Alternative check:
Measure with a DMM after settling; each capacitor reads ~6 V. Stored charge differs: Q330 = 330e-12 * 6 = 1.98 nC; Q220 = 1.32 nC.

Why Other Options Are Wrong:

• 3 V or 4 V or 2 V: No divider is present; thus not partial voltages.
• 0 V: Would imply open source or shorted capacitor; neither is stated.

Common Pitfalls:

• Confusing series capacitor division with a single-capacitor bias connection.
• Assuming capacitance changes steady-state voltage in a direct connection.

Final Answer:
6 V