In what time will Rs. 1000 amount to Rs. 1331 at 10% per annum compounded annually?

Difficulty: Easy

Correct Answer: 3 years

Explanation:


Introduction / Context:
This is a direct application of the compound interest formula to find the time needed for a principal to grow to a given amount at a known annual rate with annual compounding. The numbers are chosen to produce an exact power of a simple factor.


Given Data / Assumptions:

  • Principal P = Rs. 1000.
  • Amount A = Rs. 1331.
  • Rate of interest r = 10% per annum.
  • Interest is compounded annually.
  • Time in years t is to be determined.


Concept / Approach:

The compound interest formula for annual compounding is A = P * (1 + r / 100)^t. We substitute the known values and solve for the exponent t. Because the numbers are clean, we expect (1 + r / 100)^t to match a simple power such as (1.1)^t.


Step-by-Step Solution:

Step 1: Write the formula A = P * (1 + r / 100)^t. Step 2: Substitute P = 1000, A = 1331, r = 10%. Then 1331 = 1000 * (1 + 10 / 100)^t. Step 3: Simplify 1 + 10 / 100 to get 1.10. Step 4: The equation becomes 1331 = 1000 * (1.10)^t. Step 5: Divide both sides by 1000 to obtain 1331 / 1000 = (1.10)^t. Step 6: Recognize that 1331 / 1000 = 1.331. Step 7: Observe that (1.10)^3 = 1.331, so t = 3 years.


Verification / Alternative check:

Calculate stepwise: After 1 year amount is 1000 * 1.10 = 1100. After 2 years amount is 1100 * 1.10 = 1210. After 3 years amount is 1210 * 1.10 = 1331. This confirms that the amount of Rs. 1331 is reached at the end of 3 years.


Why Other Options Are Wrong:

After 1 year the amount is only Rs. 1100, not 1331. After 2 years it is Rs. 1210. Even after 4 years the amount would exceed Rs. 1331. Therefore, only 3 years match the required amount exactly, and the other time choices are not correct.


Common Pitfalls:

Some learners mistakenly apply simple interest, solving 1000 + 1000 * 10 * t / 100 = 1331, which gives a non integer value and does not match the compound interest setting. Others may try to interpolate between years rather than checking the powers of 1.10 directly. Remember that compound growth is exponential, so exact powers often appear in exam style problems.


Final Answer:

The required time is 3 years.

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