A train 110 metres long travels at 60 km/h. How many seconds does it take to completely cross a stationary telegraph post?

Introduction / Context:
Crossing a point object (post/pole) requires the train to travel a distance equal to its own length at its running speed.

Given Data / Assumptions:

• L = 110 m.
• v = 60 km/h.

Concept / Approach:
Convert speed to m/s, then apply t = distance / speed = L / v.

Step-by-Step Solution:

Verification / Alternative check:
Scale check: if length doubled to 220 m, time would double to 13.2 s at same speed, which is consistent.

Why Other Options Are Wrong:
5, 5.6, 6.8, 7.2 s are off from L/v after correct conversion.

Common Pitfalls:
Using km/h directly with metres; confusing platform/bridge case with post case.

Final Answer:
6.6 sec