Plastering a rectangular tank (inside walls + bottom):\nA tank is 25 m long, 12 m wide, 6 m deep. Find cost of plastering its walls and bottom at Rs 0.75 per sq. m.

Difficulty: Easy

Correct Answer: Rs. 558

Explanation:


Introduction / Context:
Compute interior area to be plastered (four walls + bottom) and multiply by the given rate.


Given Data / Assumptions:

  • Length L = 25 m, width W = 12 m, depth H = 6 m.
  • Rate = Rs 0.75 per m^2.


Concept / Approach:
Area to plaster = bottom + all four interior walls.


Step-by-Step Solution:

Bottom area = L*W = 25*12 = 300 m^2.Long walls = 2*(L*H) = 2*(25*6) = 300 m^2.Short walls = 2*(W*H) = 2*(12*6) = 144 m^2.Total = 300 + 300 + 144 = 744 m^2.Cost = 744 * 0.75 = Rs 558.


Verification / Alternative check:
Unit-check: m^2 * Rs/m^2 ⇒ Rs — consistent.


Why Other Options Are Wrong:
Other totals correspond to incorrect wall counts or missing the bottom.


Common Pitfalls:
Including the top (open tank), or double-counting a pair of walls.


Final Answer:
Rs. 558

More Questions from Area

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion