A semicircular shaped window has a diameter of 63 cm. Find its perimeter (in cm), including the curved part and the diameter (assume pi = 22/7).

Introduction / Context:
This question tests perimeter of a semicircle. A semicircle's boundary consists of two parts: the curved arc (which is half the circumference of the full circle) and the straight diameter line. Many mistakes happen when learners compute only the curved arc and forget to add the diameter, or they use radius incorrectly. Since diameter is given, first find radius, compute the semicircular arc length as pi*r, then add the diameter to get total perimeter. Units remain in centimetres throughout, and pi = 22/7 is used for neat arithmetic.

Given Data / Assumptions:

• Diameter d = 63 cm
• Radius r = d/2 = 31.5 cm
• Perimeter of semicircle = (arc length) + diameter
• Arc length of semicircle = (1/2)*2*pi*r = pi*r

Concept / Approach:
Compute arc = pi*r and then add the diameter. Use pi = 22/7 to evaluate pi*r accurately.

Step-by-Step Solution:
r = 63/2 = 31.5 cm Arc length = pi*r = (22/7)*31.5 31.5/7 = 4.5, so arc = 22*4.5 = 99 cm Perimeter = arc + diameter = 99 + 63 = 162 cm

Verification / Alternative check:
Half circumference approach: full circumference = pi*d = (22/7)*63 = 198 cm, half is 99 cm, then add diameter 63 cm gives 162 cm. Same result confirms correctness.

Why Other Options Are Wrong:
99 (not listed) would be the arc only; 132 and 142 come from wrong pi usage or wrong r. 172 is too large and suggests adding extra length beyond arc + diameter.

Common Pitfalls:
Forgetting to include diameter, using d instead of r in pi*r, or calculating half circumference incorrectly.

Final Answer:
The perimeter of the semicircular window is 162 cm.