Given total number of passengers in the bus = 45
First average weight of 45 passengers = 52 kgs
Average weight of 5 passengers who leave bus = 48
Average weight of 5 passengers who joined the bus = 54
Therefore, the net average weight of the bus is given by
Numbers of students in section A = x
? Numbers of students in section B and C = (100 ? x)
? x 70 + (100 ? x) 87.5 = 84 100
=> 70x + 87.5 100 ? 87.5x = 8400
=> 8750 ? 17.5x = 8400
=> 17.5x = 8750 ? 8400 => x = 20.
The third proportional of two numbers p and q is defined to be that number r such that
p : q = q : r.
Here, required third proportional of 10 & 20, and let it be 'a'
=> 10 : 20 = 20 : a
10a = 20 x 20
=> a = 40
Hence, third proportional of 10 & 20 is 40.
Let the three numbers be x, y, z.
From the gien data,
x = 2y ....(1)
x = z/2 => z = 2(2y) = 4y .....(From 1) ...........(2)
Given average of three numbers = 56
Then,
Now,
x = 2y => x = 2 x 24 = 48
z = 4y = 4 x 24 = 96
Now, the highest number is z = 96 & smallest number is y = 24
Hence, required sum of highest number and smallest number
= z + y
= 96 + 24
= 120.
Given that,
Number of windows = 50
Each window covering covers 15 windows
=> 50 windows requires 50/15 window coverings
= 50/15 = 3.333
Hence, more than 3 window coverings are required. In the options 4 is more than 3.
Hence, 4 window coverings are required to cover 50 windows of each covering covers 15 windows.
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