Both when accelerated through a potential difference of 100KV, they will have the same energy. The mass of the electron is less than the mass of a proton, hence it will move faster(momentum).
Q and w are path functions while q+w i.e. H, enthalpy is state function. Similarly, H-TS i.e. G, Gibbs free energy is state function.
T = 273 °K
Using the formula,
DGq = DHq ?TDS
-45 = -90 ?273 DS
DS = 0.164
Now since DHq and DSq are independent,T2= DH/DS = 45/0.164 = 273°K
Required Temp = 273 + 273 = 546°K
The Cartesian Coordinates can be retrieved from spherical coordinates (l,q,a) by:
X = r.sinq.cosa
Y = r.sinq.sina
Z = r.sinq
Using the same we get for P,
Y = P.sinq.sina
In an ideal gas, at any particular time, different particles in the gas have different speeds and hence different kinetic energies. This assumption is reasonable because as the particles collide, we expect their speed to change. Even if initial speed of all the particles was same, the molecular collisions will disrupt this uniformity.Hence statement 1 is incorrect and 2 is correct.
Hooke's law states that within the elastic limit, stress developed is directly proportional to the strain produced in a body.Hooke?s law is valid only in the linear part of stress-strain curve. Hence, statement 1 is correct.
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