Here, miscellaneous charges for 4% = 6000
Then advertisement charges for 18% = 6000 x 18/4 = Rs. 27000
Hence, required advertisement charges = Rs. 27000
Required percentage = (Advertisement charges % - Commission charges%) x 100/ Advertisement charges
Required percentage = (18 - 15 ) x 100/18 = 3 x 100 /18 = 100/6 = 162/3%
Here, 35% = Rs. 17500
Since, 15% = (17500/35 ) x 15 = Rs. 7500
Hence, required commission = Rs. 7500
Here, miscellaneous expenditures amount 4% = Rs. 1848
Then, total expenditures amount for all 100% = 1848 x 100/4 = Rs. 46200
Hence, cost of 5500 kg = Rs. 46200
then cost of 1 kg = 46200/5500 = Rs. 8.40
Hence, S.P. per kg = 125/100 x Rs. 8.40 =Rs. 10.50
As per given pie-chart , we can see that
The land used for rice is represented by 72°
The land used for barley is represented by 36°
? Required ratio = rice crops : barley crops
Required ratio = 72° : 36° = 2 : 1
From above given chart ,
? 100% = 360°
? 50% = 180°
? wheat + rice + maize = 72° + 72° + 45° = 189° > 180°
Hence the total area of wheat , rice and maize food crops is more than 50% of the total area of given food crops .
From above given graph ,
According to given option in question , Maximum expenditure of the family is on food ,which is 23%.
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