We know Compound Interest = C.I. = P1+r100t - 1
Here P = 2680, r = 8 and t = 2
C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225
= (2680 x 52 x 2)/625
= 445.95
Compound Interest = Rs. 445.95
Let the sum be Rs. P
P{
- 1 } = 2828.80
It is in the form of
P(8/100)(2 + 8/100) = 2828.80
P = 2828.80 / (0.08)(2.08)
= 1360/0.08 = 17000
Principal + Interest = Rs. 19828.80
Given principal amount = Rs. 8000
Time = 3yrs
Rate = 5%
C.I for 3 yrs =
Now, C.I for 2 yrs =
Hence, the required difference in C.I is 1261 - 820 = Rs. 441
We know that,
From given data, P = Rs. 8625
Now, C.I =
C.I =
594.5 =
% .
> 2P
Now, (6/5 x 6/5 x 6/5 x 6/5) > 2.
So, n = 4 years.
P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount =
= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05
=> C.I. = 17126 - 15625 = Rs. 1901.05.
Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A =
(P+C.I) =
(P+420) = P[11/10][11/10]
P-1.21P = -420
0.21P = 420
Hence, P = 420/0.21 = Rs. 2000
Amount =
= 8000 x 21/20 x 21/20
= Rs. 8820
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