Area problems
- 1. What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ?
Options- A. 13 m
- B. 14 m
- C. 15 m
- D. 16 m Also asked in: GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 13 m
Explanation:
The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is
=> mts.
- 2. In an old Palace there are 50 stairs to go on top floor. Each is 20 cm high, 30 cm wide and 60 cm long. If all the stairs are re-plastered at the rate of Rs. 4 per 100 sq.cm. What is the expenditure ?
Options- A. Rs. 4680
- B. Rs. 7600
- C. Rs. 6000
- D. Rs. 5480 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: Rs. 6000
Explanation:
Total are of all stairs = 50 (20x60 + 30x60)
= 50 (1200 + 1800)
= 50 x 3000
= 150000 sq cm.
Given rate of 100 sq cm = Rs. 4
Then for 150000 sq. cm = ?
=> 4 x 150000/100 = Rs. 6000
- 3. The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ?
Options- A. 12.50 cm
- B. 14.21 cm
- C. 15.98 cm
- D. 17.08 cm Also asked in: CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 17.08 cm
Explanation:
Let the length of the rectangle = L cm
Then the breadth of the rectangle = (L - 10) cm
Perimeter of a rectangle = 2(L + B) cm
=> 44 = 2(L + L - 10)
=> 44 = 4L - 20
=> 4L = 64
=> L = 16 cm
=> B = L - 10 = 6 cm
Diagonal = = = 17.08 cm
- 4. The diagonal of the floor of a rectangular closet is 7 12 feet. The shorter side of the closet is 4 12 feet. What is the area of the closet in square feet?
Options- A. 9
- B. 18
- C. 27
- D. 36 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 27
Explanation:
Other side = = = = 6 ft
Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.
- 5. The length of a rope in meter by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is ?
Options- A. 15 mts
- B. 30 mts
- C. 24 mts
- D. 36 mts Also asked in: GRE, GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 30 mts
Explanation:
The cow can graze an area of 2826 sq.m i.e it is able to cover area of circle of 2826 sq.m
Therefore,
=2826
=(2826×7/22) = 899.18 = 900
r = 30 m.
Therefore, the radius of the circle implies the length of the rope = 30 mts.
- 6. An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
Options- A. Rs. 4082.40
- B. Rs. 1024.21
- C. Rs. 2810.6
- D. Rs. 3214 Also asked in: AIEEE, Bank Exams, CAT, GATE, Bank Clerk, Bank PO
Correct Answer: Rs. 4082.40
Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
- 7. What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?
Options- A. 844
- B. 814
- C. 840
- D. 820 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) sq.cm
Required number of tiles =1517 x 902/(41 x 41) = 814.
- 8. The edge of three cubes of metal is 3 m, 4 m and 5 m. They are melted and formed into a single cube. Find the edge of the new cube ?
Options- A. 15 m
- B. 4 m
- C. 6 m
- D. 9 m Also asked in: GRE, GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk
Correct Answer: 6 m
Explanation:
The edge of the new cube is = => a = 6 m.
- 9. A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?
Options- A. 115
- B. 117
- C. 116
- D. 114 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 117
Explanation:
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
- 10. Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ?
Options- A. 720
- B. 600
- C. 660
- D. 6000 Also asked in: AIEEE, Bank Exams, CAT, Bank Clerk, Bank PO
Correct Answer: 720
Explanation:
Let the number of bricks be 'N'
10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N
10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
Programming
Copyright ©CuriousTab. All rights reserved.