Cubes and Dice problems

There is 6 columns with 2 cubes each.
Total boxes = 6 × 2 = 12

4 columns with 1 cubes = 4 cubes
1 columns with 3 cubes = 3
1 columns with 4 cubes = 4
Total cubes = 4 + 3 + 4 = 11

On the basis of question figure pattern , we can see that
The numbers 1, 2, 5 and 6 are on the faces adjacent to the number 4.
So, the number 3 lies opposite 4.
The numbers 1, 3, 4 and 6 lies on the faces adjacent to the number 2.
So, the number 5 lies opposite 2.
Now, the number 1 lies opposite 6.

On the basis of question figure pattern ,
One dot, three dots, five dots and six dots is/are on the faces adjacent to two dots.
Therefore, four dots are on face opposite to two dots.
One dot, two dots and six dots is/are on the faces adjacent to three dots.
Therefore, five dots are on the face opposite to three dots.
Thus, six dots lie opposite one dot.

As per the given above open dice , we have
When folded in the form of a cube, then 'F' appears opposite 'B'; 'E' appears opposite 'C' and 'A' appears opposite 'D'.
In option (1) 'F' is adjacent to 'B'.
In option (3) 'E' is adjacent to 'C'.
In option (4) 'D' is adjacent to 'A'.

From the above given diagram , we can say that
Six cubes are visible and four cubes are hidden.
Thus , there are 10 cubes .