Area problems
- 1. The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?
Options- A. 3 cm
- B. 4 cm
- C. 6 cm
- D. 8 cm Also asked in: Bank Exams, Bank PO
Correct Answer: 6 cm
Explanation:
Let height =x Then, base =2x
2x * x = 72
=>x=6
- 2. The ratios of areas of two squares, one having its diagonal double than the other is
Options- A. 2:1
- B. 2:3
- C. 3:1
- D. 4:1 Also asked in: Bank Exams, Bank PO
Correct Answer: 4:1
Explanation:
ratio =
- 3. A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?
Options- A. 156
- B. 166
- C. 176
- D. 186 Also asked in: Bank Exams, Bank PO
Correct Answer: 176
Explanation:
Area of the room=(544 * 374)
size of largest square tile= H.C.F of 544 & 374 = 34 cm
Area of 1 tile = (34 x 34)
Number of tiles required== [(544 x 374) / (34 x 34)] = 176
- 4. Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
Options- A. 30
- B. 40
- C. 50
- D. 60 Also asked in: Bank Exams, Bank PO
Correct Answer: 30
Explanation:
Height of the triangle = = 5 cm.
Its area = = = .
- 5. The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle.
Options- A. 30
- B. 40
- C. 50
- D. 60 Also asked in: Bank Exams, Bank PO
Correct Answer: 40
Explanation:
let length = 2x and breadth = x then
(2x-5) (x+5) = (2x * x)+75
5x-25 = 75 => x=20
length of the rectangle = 40 cm
- 6. The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?
Options- A. 150
- B. 250
- C. 350
- D. 550 Also asked in: Bank Exams, Bank PO
Correct Answer: 250
Explanation:
Circumference = No.of revolutions * Distance covered
Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.
- 7. A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.
Options- A. 136
- B. 146
- C. 166
- D. 176 Also asked in: Bank Exams, Bank PO
Correct Answer: 176
Explanation:
area of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176
- 8. Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.
Options- A. 84
- B. 64
- C. 44
- D. 22 Also asked in: Bank Exams, Bank PO
Correct Answer: 84
Explanation:
Let a = 13, b = 14 and c = 15. Then, =21
(s- a) = 8, (s - b) = 7 and (s - c) = 6.
Area =
=
= 84 sq.cm
- 9. The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Options- A. 20%
- B. 30%
- C. 40%
- D. 50% Also asked in: Bank Exams, Bank PO
Correct Answer: 50%
Explanation:
Let original length = x and original breadth = y.
Original area = xy.
New length = x/2 and New breadth=3y
New area =
Therefore, Increase in area = New area-original area =
Therefore, Increase % = %
- 10. The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is
Options- A. 5100 sq.m
- B. 4870 sq.m
- C. 4987 sq.m
- D. 4442 sq.m Also asked in: AIEEE, Bank Exams, CAT, GATE, Analyst, Bank Clerk, Bank PO, IT Trainer
Correct Answer: 5100 sq.m
Explanation:
Let the breadth of floor be 'b' m.
Then, length of the floor is 'l = (b + 25)'
Area of the rectangular floor = l x b = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 sq.m.
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