Let the radius of the circle be r cm. Then,
r=3.
Volume of the cylindrical ditch = ?rxrh = 22/7 ×7×7×2 = 308 sq.m
Area of remaining field = (X ??rxr) sq.m
= (X ? 154)
ATQ ?
(X ? 154) ×0.77 = 308
(X ? 154) = 400
X= 554 sq.m
Let the inner and outer radii be r and R metres.
Then
=> Width of the ring = (R - r) = (12 - 8) m = 4 m.
We know that,
Perimeter of rectangle = 2(L+W) = 2(5 + 2) = 2 (7) = 14 fts.
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