Static HIGH-state dissipation Given ICCH = 1.1 mA at VCC = 5 V and the gate is held in a static HIGH output state (no switching), what is the power dissipation PD?
Digital Electronics
Integrated Circuit Technologies
Difficulty: Easy
Choose an option
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A5.5 mW
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B5.5 W
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C5 mW
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D1.1 mW
Answer
Correct Answer: 5.5 mW
Explanation
Introduction / Context:Static power in logic is simply supply voltage times the specified static current in a particular state. Manufacturers often list ICCH (HIGH) and ICCL (LOW) currents separately.
Given Data / Assumptions:
- ICCH = 1.1 mA.
- VCC = 5 V.
- No switching (ignore dynamic power).
Concept / Approach:Use PD = VCC * ICC for the given static state.
Step-by-Step Solution:PD = 5 V * 1.1 mA = 5.5 mW.
Verification / Alternative check:Units: volts * amperes = watts. 5 * 0.0011 = 0.0055 W = 5.5 mW.
Why Other Options Are Wrong:5.5 W: off by a factor of 1000 (mA vs A).5 mW and 1.1 mW: arithmetic errors.
Common Pitfalls:Dropping the milli prefix or mixing µA/mA leads to thousandfold mistakes.
Final Answer:5.5 mW