Static HIGH-state dissipation Given ICCH = 1.1 mA at VCC = 5 V and the gate is held in a static HIGH output state (no switching), what is the power dissipation PD?

Introduction / Context:
Static power in logic is simply supply voltage times the specified static current in a particular state. Manufacturers often list ICCH (HIGH) and ICCL (LOW) currents separately.

Given Data / Assumptions:

• ICCH = 1.1 mA.
• VCC = 5 V.
• No switching (ignore dynamic power).

Concept / Approach:
Use PD = VCC * ICC for the given static state.

Step-by-Step Solution:
PD = 5 V * 1.1 mA = 5.5 mW.

Verification / Alternative check:
Units: volts * amperes = watts. 5 * 0.0011 = 0.0055 W = 5.5 mW.

Why Other Options Are Wrong:
5.5 W: off by a factor of 1000 (mA vs A).5 mW and 1.1 mW: arithmetic errors.

Common Pitfalls:
Dropping the milli prefix or mixing µA/mA leads to thousandfold mistakes.

Final Answer:
5.5 mW