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- Question
- What was the day of the week on 5th June, 2002?
Options- A. Wednesday
- B. Saturday
- C. Friday
- D. Monday
- Correct Answer
- Wednesday
ExplanationPeriod upto 5th June, 2002 = (2001 yr + Period from 1.1.2002 to 5.6.2002)
? Odd days in 1600 yr = 0
Odd days in 400 yr = 0
Odd days in 1 ordinary year = 1
Odd days in 2001 year = (0 + 0 + 1) = 1
Number of days from 1.1.2002 to 5.6.2002
January + February + March + April + May + June
= 31 + 28 + 31 + 30 + 31 + 5
= 156 days = 22 weeks + 2 days
= 2 odd days
? Total number of odd days = (1 + 2) = 3
? The required day is Wednesday. - 1. What was the day of the week on 17th August, 2010?
Options- A. Sunday
- B. Wednesday
- C. Tuesday
- D. Friday Discuss
- 2. On what day dates March, 2005 did Saturday fall?
Options- A. 4th, 5th, 9th, 12th
- B. 5th, 12th, 19th, 26th
- C. 3rd, 10th, 17th, 25th
- D. 4th, 11th, 18th, 25th Discuss
- 3. The last day of a century cannot be?
Options- A. Thursday
- B. Wednesday
- C. Friday
- D. Mondey Discuss
- 4. What was the days of the week on 17th August , 2010?
Options- A. Sunday
- B. Wednesday
- C. Tuesday
- D. Friday Discuss
- 5. What was the day of the week on 17th July, 1776?
Options- A. Wednesday
- B. Thursday
- C. Monday
- D. Saturday Discuss
- 6. Find at what time between 8 and 9 O'clock will the hands of a clock be in the same straight line but not together?
Options- A. 11 9 minutes past 5 11
- B. 9 7 minutes past 5 11
- C. 10 10 minutes past 8 11
- D. None of these Discuss
- 7. Find the angle between the two hands of a clock at 30 minutes past 4 O'clock.
Options- A. 40°
- B. 30°
- C. 45°
- D. None of these Discuss
- 8. My watch gains 5 seconds in 3 minutes was set right at 7 am. In the afternoon of the same day, when the watch indicates quarter past 4 O'clock, the true time is:
Options- A. 59 7 minutes past 3 12
- B. 12 3 minutes past 3 11
- C. 4 pm
- D. 7 5 minutes past 4 12 Discuss
- 9. A clock gains 10 minutes in every 24 hours. It is set right on Monday at 8 am. What will be the correct time on the following Wednesday, when the watch indicates 6 pm?
Options- A. 5 : 36 pm.
- B. 5 : 40 pm.
- C. 4 : 36 pm.
- D. None of these Discuss
- 10. A watch which gains uniformly is 6 minutes slow at 4 pm on a Sunday and 102/3 minutes fast on the following Sunday at 8 pm. During this period (Day and Time) when was the watch correct?
Options- A. 2 : 36 am
- B. 1 : 36 am
- C. 2 : 36 pm
- D. 1 : 36 pm Discuss
Calendar problems
Search Results
Correct Answer: Tuesday
Explanation:
Period upto 17th August, 2010 = (2009 yr + Period from 1.1.2010 to 17.8. 2010)
Counting of odd days
Odd day in 1600 yr = 0
Odd days in 400 yr = 0
9 yr = (2 leap years + 7 ordinary years)
= ( 2 x 2 + 7 x 1) = 1 week + 4 days = 4 odd days
Number of days between 1.1.2010 to 17.8.2010
January + February + March + April + May + June + July + August.
= (31 + 28 + 31 + 30 + 31 + 30 + 31 + 17) days
= 229 days = 32 weeks + 5 odd days
Total number of odd days = (0 + 0 + 4 + 5 ) days
= 9 days = 1 week + 2 odd days
Hence, the required day is Tuesday.
Correct Answer: 5th, 12th, 19th, 26th
Explanation:
First, we find out the day on 1.03.2005. Period upto 1.3.2005.
= (2004 yr + Period from 1.1.2005 to 1.3.2005)
? Odd day in 1600 yr = 0
Odd day in 400 yr = 0
4 yr = (1 leap year + 3 ordinary years)
= (1 x 2 + 3 x 1) = 5 odd days
Number of days between 1.1.2005 to 1.3.2005,
= January + February + March
= 31 + 28 + 1
= 60 days = (8 weeks + 4 days)
= 4 odd days
Total number of odd days
= (0 + 0 + 5 + 4) = 9
= 1 weak + 2 odd days
? 1.3. 2005 was Tuesday.
So, Saturday will fall on 5.3.2005.
Hence, Saturday lies on 5th, 12th, 19th, and 26th of March 2005.
Correct Answer: Thursday
Explanation:
100 yr have 5 odd days.
? Last day of 1st century of is Friday.
200 yr have (5 x 2) = 1 week + 3 odd day = 3 odd day
? Last day of 2nd century of Wednesday,
300 yr have (5 x 3) = 2 week + 1 odd day = 1 odd day
? Last day of 3rd century is Monday.
400 yr have 0 odd day.
? Last day of 4th century is Sunday.
This cycle is repeated.
? Last day of a century cannot be Tuesday of Thursday of Saturday.
Correct Answer: Tuesday
Explanation:
Period up to 17th August, 2010 = (2009 yr + Period from 1.1.2010 to 17.8.2010)
Counting of odd days
Odd day in 1600 yr = 0
Odd days in 400 yr = 0
9 yr = (2 leap year + 7 ordinary years) = (2 x 2 + 7 x 1 ) = 1 Week + 4 days = 4 odd days
Number of days between 1.1.2010 to 17.8.2010
January + February + March + April + May + June + July + August.
= (31 + 28 + 31 + 30 + 31 + 30 + 31 + 17) days
= 229 days = 32 weeks + 5 odd days
Total number of odd days
= (0 + 0 + 4 + 5) days = 9 days
= 1 week + 2 odd days
Hence, the required day is Tuesday.
Correct Answer: Wednesday
Explanation:
Period upto 17th July, 1776 = 1775 yr + Period from 1st January 1776 to 17th July 1776
Counting of odd days
In 1600 yr = 0
In 100 yr = 5
75 yr = 18 leap years + 57 ordinary years = (18 x 2 + 57 x 1) odd days
= 93 odd days
= 13 weeks + 2 days
= 2 odd days
? 1775 yr have(0 + 5 + 2) odd days
= 7 odd days = 1 week + 0 odd day
= 0 odd day
Number of days between 1.1.1776 to 17.7.1776
January + February + March + April + May + June + July
31 + 29 + 31 + 30 + 31 + 30 + 17 = 199 days = 28 weeks + 3 odd days
? Total number of odd days = (3 + 0) = 3
Hence, the required day is Wednesday.
Correct Answer: 10 10 minutes past 8 11
Explanation:
Correct Answer: 45°
Explanation:
Correct Answer: 4 pm
Explanation:
Correct Answer: 5 : 36 pm.
Explanation:
Correct Answer: 1 : 36 am
Explanation:
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