A clock is set to show the correct time at 7 am Monday. The clock losses 15 min in 24 h. What will be the true time when the clock indicates 6 am on the following Friday?

Since, angle between two number is 360°/12 = 30°
When the time is 3:25 pm, the minute hand will be at 5 and will have moved 60° from 3 and hour hand would be between 3 and 4 it will move 30° in 60 min and so in 25 min it would have moved 30 x 25/60 = 12.5°
So, angle between two hand will be 60 - 12.5 = 47.5°

Director came at 12 : 15.
Steno came at 12 : 40.
Since, steno was late by 30 min to the meeting.
? Meeting time 12 : 10

The angle between hour hand and minute hand at 5 O'clock = 5 x 30° = 150°
Minute hand move in 10 min = 2 x 30° = 60°
Hour hand move in 10 min = 30°/6 = 5°
? Angle between hour hand and minute hand at 5 h 10 min = 150° - 60° + 5deg; = 95°

1st day of month is Monday.
6th day of month is Saturday.
13th day of month is second Saturday.
17th day is the fourth day after second Saturday.

Three days earlier than Friday means Tuesday.
So, 7th day of month will be Tuesday.
14th day of month will be Tuesday.
19th day of month will be Sunday.

At 9 o'clock, the hour hand is at 9 and the minute hand is at 12. it means that the two hands are 15 min spaces apart .To be in the same straight line (but not together ), they will be 30 min space apart .
? The minute hand will have to gain (30 - 15) = 15 min space over the hour hand .

As we Know, 55 min spaces are gained in 60 min.
? 15 min will be gained in (60/55 x 15) min = 180/11 = 16⁴ /₁₁ min

Hence, the hands will be in the same straight line but not together at 16⁴/ ₁₁ min past 9.

Given that n = 2 and (n + 1) = 3(n < 6)
The hands will be at the same straight line at
? (5n + 30) x 12/11 min past n.
? (5 x 2 + 30 ) x 12/11 min past 2.
? (10 + 30) x 12/11 min past 2.
? 40 x 12/11 min past 2.
? 480/11 min past 2.

Time from 6 am on a day to 11 pm on 4th day = 89 h
Now, 23 h 44 min of this clock = 24 h of correct clock
89 h of this clock = 24 x (15/356) x 89 h of correct clock = 90 h of correct clock
? Correct time will be 12 o' clock (mid-night).

Time from 9 pm in a day to 2 pm on the following day = 29 h.
24 h 10 min of this clock = 24 h of the correct clock
or 145/6 h of this clock = 24 h of the correct clock
29 h of this clock = 24 x (6/145) x 29 h of the correct clock
= 28 h 48 min of correct clock
? The correct time is 28 h 48 min after 9 am. This will be 48 min past 1.

Given that, time to overtake N = 70 min

The required result = [(720/11) - N) ] x [(60 x 24)/N) min
= [(720/11) - 70) ] x [(60 x 24)/70) min
= [(720 - 770) / 11] x [(60 x 24) / 70] min
= - (50/11) x [(6 x 24)] / 7 min = -7200/77 min
-ve sign indicates that there is a loss.