On January 12, 1980, it was Saturday. The day of the week on January 12, 1980, it was Saturday. The day of the week on January 12, 1979 was?

Counting the number of days after 3rd November, 1987 we have Nov., Dec., Jan., Feb., March., April.

So days = 27 + 31 + 31 + 29 + 31 + 4 = 153 days containing 6 odd days on 4th April, 1988.
So, the day was Tuesday.

As per the given above question ,we can say that
Odd number of days from September 6, 1970 to September 6, 1981 = 14 days
Hence, the Sunday will be on September 6, 1981.

As we know that ,
In an ordinary year, February has no odd day.
? February and March begin on same day of the week.
Also we know that, November and March begin on same day of the week.
Hence , required answer will be February and November .

1992 being a leap year, it has 2 odd days. So, the first day of the year 1993 will be two days beyond Wednesday i.e., it will be Friday.

1600 years of 0 odd days and 30 years have 1 odd day. 49 years contain 12 leap years and 37 ordinary years and therefore (24 + 37) odd days i.e., 5 odd days i.e., 1949 years contain (0 + 1 + 5) = 6 odd days. 26 day of January contain 5 days.Total odd days = (6 + 5) = 11 or 4 days. So, the days was Thursday

This being a leap year none of the next 3 year is a leap year. So, the day of the week will be 3 days beyond Monday i.e., it will be Thursday.

Clock will make right angle at (5n + 15) x 12/11 min past n.
Given that, n = 3
? Clock will make right angle at ( 5 x 3 + 15 ) x 12/11 min past 3 . =30 x 12 / 11 min past 3.
= 32⁸/₁₁ min
So required time = 3 H 32⁸/₁₁ min

Angle traced by hour hand in 12 h = 360°
Angle traced by hour hand in 25/4 h = (360/12) x (25/4)° = 187.5°
Angle traced by minute hand in 60 min = 360°
Angle traced by it in 15 min = (360/60) x 15° = 90°
? Required angle = (187.5° - 90°) = 97.5°