How many days are three from 2nd January 1993 to 15th march 1993?

The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

? 2nd July, 1984 was Monday

Each day of the week is repeated after 7 days
? After 63 days, it would be Friday
So, After 62 days, it would be Thursday

For two years having same calendar must have two common conditions: both having same length in terms of number of days and first day of the week.

The year 1991 has 365 days,,that is 1 odd day , year 1992 has 366 days , i.e. 2 odd days , year 1993 has 365 days i.e. 1 odd day. the years 1994,1995,1996 have 1 odd day each.

the sum of odd days so calculated from year 1990 to 1996 .
(1+2+1+1+1+1)=7 odd days. 5

hence, the year 1997 will have same calendar as that of year 1990.

Let us assume the present ages of Mohan and Sohan be 3x years and 4x years; then,
4 Four years ago the ages was 3x - 4 and 4x - 4 years.
According to question, 4 Four years ago the ratio was 5 : 7
( 3x - 4 ) / ( 4x - 4 ) = 5/7
? ( 3x - 4 ) 7 = 5 ( 4x - 4 )
? 21x - 28 = 20x - 20
? 21x - 20x = 28 - 20
? x = 8
Hence, their present ages, 3x = 3 x 8 = 24 years; 4x = 4 x 8 = 32 years.
So their present ages 24 and 32 years.

When Ravi was born, his mother's age was 26 yr and his elder brother was 3 yr elder to him.
? Mother's age when brother was born
= 26 - 3 = 23 yr
Ravi's father was 28 yr of age when his sister was born and his sister was 4 yr of age when his brother was born
? Age of father when brother was born
= 28 + 4 = 32 yr

Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
? Calendar for 1993 is the same as that of 1988.

A leap year has (52 week + 2 days).
So, the number of odd days in a leap year is 2

Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h
and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min
? Total hours and minutes = 12 h + 1 h 48 min
= 13 h and 48 min

Here, n = 3 and (n + 1) = 4
? Two hands will coincide at 60n / 11 min past n
? 60 x 3 / 11 min past 3
? 180 /11 min past 3.
? 16⁴/Sub>11 min past 3

A leap year must be divisible by 4 as every 4th year is a leap year..