Let the present age of Pradhan be P years and his father's age = Q years.
From 1st condition,
(P + 6) = (Q + 6 ) x 3/7
? 7P + 42 = 3Q + 18
? 7P - 3Q = -24 ...(i)
From 2nd condition
(P - 10) / (Q - 10) = 1/5
? 5P - 50 = Q - 10
? 5P - Q = 40 .....(ii)
Multiplying equation (ii) by 3 and subtracting from (i) we get
P = 18, Q = 50
So present age of Pradhan's father = 50 years.
P + R + 2 Q = 59, ....(i)
Q + R + 3 P = 68 .....(ii)
and P + 3 (Q + R) = 108 ......(iii)
Solving the above three equations, we get
? P + 3 (68 - 3P) = 108
? P + 204 - 9P = 108
? P = 12 years.
Let the ages of Harish and Seema be x and y respectively.
According to the question,
xy = 240 ....(i)
2y - x = 4 ....(ii)
Solving equations (i) and (ii), we get
y = 12 years
? S / F = 1 / 5
? F = 5 S, .....(i)
? M / F = 4 / 5
? M = 4 / 5 F ....(ii)
? (S + 2) / (M + 2) = 3 / 10
? 10S + 20 = 3M + 6 ....(iii)
From (i), (ii) and (iii)
? (12 - 10)S = 20 - 6
? 2S = 14
? S = 7 years
? F = 5S = 5 x 7 = 35 years.
Let A's age = x years and B's age = y years
As per the first condition,
? (x + 15) = 2(y + 15)
? x - 2 y = 15 ....(i)
As the per second condition,
? (x - 5) = 4(y - 5)
? x - 4 y = -15 ....(ii)
Solving (i) and (ii) one get's, x = 45, y = 15
? A's age = 45 years
B's age = 15 years
? Difference of their ages = 45 - 15 = 30 years
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
Let the present age of Kunal be 3x year and the
present age of Ganesh = 5x years.
According to question ,
(5x + 4 ) - (3x + 4 ) = 12
? 2x = 12
? x = 6
? Present age of Kunal = 3x = 3 x 6 = 18 year
Relative speed = (84 + 60) km/h = 144 km/h = 144 x (5/18) = 8 m/s
Distance covered in passing each other = 512 + 528 = 1040 m
? Required time = 1040/40 = 26 s
? Total age of father and mother = 35 x 2 = 70 yr
and total age of father, mother and son = 27 x 3 = 81 yr
&there4: Age of son = 81 -70 = 11 yr
? Total age of 9 students and a teacher = 10 x 16 = 160 yr
Total age of first 4 students = 4 x 19 = 76 yr
and total age of last 5 students = 5 x 10 = 50 yr
? Age of teacher = 160 - 76 - 50 = 34 yr
Let the present age of Varun be M and present age of Kapil be N.
According to the questions,
M + N = 42 ...(i)
Again, according to the question, After 5 yr,
(M + 5)/(N + 5) = 15/11
? 11M + 55 = 15N + 75
? 11M - 15N = 20 ...(ii)
On solving Eqs. (i) and (ii),
? N = 17 yr
Hence, present age of Kapil = 17 yr
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