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- Question
- If the age of P and R are added to twice the age of Q the total becomes 59. If the ages of Q and R are added to thrice the age of P the total becomes 68. And if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. what is the age of P T?
Options- A. 15 years
- B. 19 years
- C. 17 years
- D. 12 years
- Correct Answer
- 12 years
ExplanationP + R + 2 Q = 59, ....(i)
Q + R + 3 P = 68 .....(ii)
and P + 3 (Q + R) = 108 ......(iii)
Solving the above three equations, we get
? P + 3 (68 - 3P) = 108
? P + 204 - 9P = 108
? P = 12 years. - 1. The product of the ages of Harish and Seema is 240 . If twice the age of seema is more then Harish's age by 4 years. What is seema's age in years?
Options- A. 12 years
- B. 20 years
- C. 10 years
- D. 14 years Discuss
- 2. The ratio of the present ages of a son and his father is 1 : 5 and that of his mother and father is 4 : 5. After 2 years the ratio of the age of the son to that of his mother becomes 3 : 10. What is the present age of the father?
Options- A. 30 years
- B. 28 years
- C. 27 years
- D. None of these Discuss
- 3. 15 years later, A will be twice as old as B but five years ago A was 4 times as old as B. Find the difference of their present ages?
Options- A. 15 years
- B. 45 years
- C. 30 years
- D. 25 years Discuss
- 4. A says to B "I am twice as old as you were when I was as old as you are." The sum of their ages is 63 years. Find the difference of their ages?
Options- A. 27 years
- B. 12 years
- C. 9 years
- D. 6 years Discuss
- 5. A is as much younger than B as he is older then C. If the sum of B's and C's age is 40 years. Find the age of A.?
Options- A. 20 years
- B. 25 years
- C. 30 years
- D. 27 years Discuss
- 6. After 6 years Pradhan's age will be 3/7 times the age of his father. 10 years ago the ratio in the age of Pradhan and his father was 1 : 5. What is the present age of Pradhan's father?
Options- A. 40 years
- B. 50 years
- C. 56 years
- D. Data is inadequate Discuss
- 7. The ratio between present age of Kunal and Ganesh is 3 : 5. If 4 years later Kunal will be younger then Ganesh by 12 years. What is the present age of Kunal?
Options- A. 17 years
- B. 19 years
- C. 22 years
- D. None of these Discuss
- 8. Two trains of length 512 m and 528 m are running towards each others on parallel lines at 84 km/h and 60 km/h, respectively. In what time, will they be clear of each other from the moments they meet?
Options- A. 26 s
- B. 25 s
- C. 15 s
- D. 27 s Discuss
- 9. In a family, the average age of father and mother is 35 yr. The average age of the father, mother and their only son is 27 yr. What is the age of the son?
Options- A. 12 yr
- B. 11 yr
- C. 10.5 yr
- D. 10 yr Discuss
- 10. The average age of 9 students and their teacher is 16 yr. The average age of the first four students is 19 yr and that of the last five is 10 yr. The teacher's age is?
Options- A. 36 yr
- B. 34 yr
- C. 30 yr
- D. 28 yr Discuss
Problems on Ages
Search Results
Correct Answer: 12 years
Explanation:
Let the ages of Harish and Seema be x and y respectively.
According to the question,
xy = 240 ....(i)
2y - x = 4 ....(ii)
Solving equations (i) and (ii), we get
y = 12 years
Correct Answer: None of these
Explanation:
? S / F = 1 / 5
? F = 5 S, .....(i)
? M / F = 4 / 5
? M = 4 / 5 F ....(ii)
? (S + 2) / (M + 2) = 3 / 10
? 10S + 20 = 3M + 6 ....(iii)
From (i), (ii) and (iii)
? (12 - 10)S = 20 - 6
? 2S = 14
? S = 7 years
? F = 5S = 5 x 7 = 35 years.
Correct Answer: 30 years
Explanation:
Let A's age = x years and B's age = y years
As per the first condition,
? (x + 15) = 2(y + 15)
? x - 2 y = 15 ....(i)
As the per second condition,
? (x - 5) = 4(y - 5)
? x - 4 y = -15 ....(ii)
Solving (i) and (ii) one get's, x = 45, y = 15
? A's age = 45 years
B's age = 15 years
? Difference of their ages = 45 - 15 = 30 years
Correct Answer: 9 years
Explanation:
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
Correct Answer: 20 years
Explanation:
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
Correct Answer: 50 years
Explanation:
Let the present age of Pradhan be P years and his father's age = Q years.
From 1st condition,
(P + 6) = (Q + 6 ) x 3/7
? 7P + 42 = 3Q + 18
? 7P - 3Q = -24 ...(i)
From 2nd condition
(P - 10) / (Q - 10) = 1/5
? 5P - 50 = Q - 10
? 5P - Q = 40 .....(ii)
Multiplying equation (ii) by 3 and subtracting from (i) we get
P = 18, Q = 50
So present age of Pradhan's father = 50 years.
Correct Answer: None of these
Explanation:
Let the present age of Kunal be 3x year and the
present age of Ganesh = 5x years.
According to question ,
(5x + 4 ) - (3x + 4 ) = 12
? 2x = 12
? x = 6
? Present age of Kunal = 3x = 3 x 6 = 18 year
Correct Answer: 26 s
Explanation:
Relative speed = (84 + 60) km/h = 144 km/h = 144 x (5/18) = 8 m/s
Distance covered in passing each other = 512 + 528 = 1040 m
? Required time = 1040/40 = 26 s
Correct Answer: 11 yr
Explanation:
? Total age of father and mother = 35 x 2 = 70 yr
and total age of father, mother and son = 27 x 3 = 81 yr
&there4: Age of son = 81 -70 = 11 yr
Correct Answer: 34 yr
Explanation:
? Total age of 9 students and a teacher = 10 x 16 = 160 yr
Total age of first 4 students = 4 x 19 = 76 yr
and total age of last 5 students = 5 x 10 = 50 yr
? Age of teacher = 160 - 76 - 50 = 34 yr
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