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- Question
- If C's age is twice the average age of A, B and C, A's age is one half the average of A, B and C. If B is 5 years old, the average age of A, B and C is?
Options- A. 10 years
- B. 15 years
- C. 12 years
- D. 9 years
- Correct Answer
- 10 years
ExplanationLet the average age of A, B and C be N years.
? Total age of A, B and C = 3 x N = 3N years
Now, according to the question,
? 3N - (2N + N/2) = 5
? N = 10 years. - 1. A father's age is three times the sum of the ages of his two children but 20 years hence his age will be equal to the sum of their ages. Then the father's age is?
Options- A. 30 years
- B. 40 years
- C. 35 years
- D. 45 years Discuss
- 2. The sum of the ages of the father and son is 45 years. Five years ago, the product of their ages was four times of the father's age at that time, then the present ages of the father and son respectively are .... and .... years.?
Options- A. 39, 6
- B. 35, 10
- C. 36, 9
- D. 40, 10 Discuss
- 3. If 6 years are subtracted from the present age of Randheer and the remainder is divided by 18 than the present age of his grandson Anup is obtained. If Anup is 2 years younger to mahesh whose age 5 years, then what's the age of Randheer?
Options- A. 96 years
- B. 84 years
- C. 48 years
- D. 60 years Discuss
- 4. Shyam is 3 times as old as his son. After 10 years the sum of their ages will be 76 years. the respective ages of the father and the son are .... and .... years.?
Options- A. 42, 14
- B. 39, 13
- C. 45, 15
- D. None of these Discuss
- 5. The ratio of Mona's age to the age of her mother is 5 : 15. The difference of their ages is 24 years. The ratio of their ages After 3 years will be?
Options- A. 1 : 3
- B. 2 : 3
- C. 3 : 7
- D. None of these Discuss
- 6. Two years ago, a mother was four times as old as her daughter. 8 years later, mother's age will exceed her daughter's age by 12 years. The ratio of the present ages of mother and daughter is?
Options- A. 3 : 1
- B. 4 : 1
- C. 3 : 2
- D. 5 : 1 Discuss
- 7. Five years ago, the total of the ages of father and son was 60 years. The ratio of their present ages is 4 : 1. Then the present age of the father is?
Options- A. 48 years
- B. 51 years
- C. 56 years
- D. 61 years Discuss
- 8. A is as much younger than B as he is older then C. If the sum of B's and C's age is 40 years. Find the age of A.?
Options- A. 20 years
- B. 25 years
- C. 30 years
- D. 27 years Discuss
- 9. A says to B "I am twice as old as you were when I was as old as you are." The sum of their ages is 63 years. Find the difference of their ages?
Options- A. 27 years
- B. 12 years
- C. 9 years
- D. 6 years Discuss
- 10. 15 years later, A will be twice as old as B but five years ago A was 4 times as old as B. Find the difference of their present ages?
Options- A. 15 years
- B. 45 years
- C. 30 years
- D. 25 years Discuss
Problems on Ages
Search Results
Correct Answer: 30 years
Explanation:
Let the present age of father be x years and the sum of present ages of 2 sons be y years.
? x = 3y ...(i)
? (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]
Solving (i) and (ii), we get
x = 30 years
Correct Answer: 36, 9
Explanation:
Let son's present age be x years and father's age = (45 - x) years.
? (x - 5) (45 - x - 5) = 4 ( 45 - x - 5)
? (40 - x) (x - 9) = 0
? x = 9years
? The son's age = 9 years
Father's age = 45 - 9 = 36 years
Correct Answer: 60 years
Explanation:
? Anup's age = (5 - 2) years = 3 years
Let Randheer's age be x years.
Then, (x - 6)/18 = 3
? x = 54 + 6 = 60
Correct Answer: 42, 14
Explanation:
Let son's age present age be x years .
? Father's present age = 3x years
Son's age 10 years hence = ( x + 10) years
Father's age 10 years hence = (3x + 10)
As per the condition ,
? ( x + 10) + (3x + 10) = 76
? 4x = 56
? x = 14
? Son's present age = 14 years
Father's present age = 42 years
Correct Answer: 3 : 7
Explanation:
Let the age of Mona and her mother be 5x and 13x years respectively.
Then, (13x - 5x) = 24
? x = 3
So, their present ages are 15 years and 39 years
Ratio of their ages after 3 years = 18 : 42 = 3 : 7
Correct Answer: 3 : 1
Explanation:
Let the mother's age 2 years ago be 4x and daughter's age 2 years ago be be x.
? (4x + 8) - (x + 8) = 12
? 3x = 12
? x = 4
? Mother's present age = 4x + 2 = 18 years
and daughter's present age = x + 2 = 6 years
? Required ratio = 3 : 1
Correct Answer: 56 years
Explanation:
Let the present age of the son be x and that of the father be 4x years.
? (x - 5) + (4x - 5) = 60
? 5x = 70
? x = 14 years
? Father's present age = 4x = 56 years
Correct Answer: 20 years
Explanation:
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
Correct Answer: 9 years
Explanation:
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
Correct Answer: 30 years
Explanation:
Let A's age = x years and B's age = y years
As per the first condition,
? (x + 15) = 2(y + 15)
? x - 2 y = 15 ....(i)
As the per second condition,
? (x - 5) = 4(y - 5)
? x - 4 y = -15 ....(ii)
Solving (i) and (ii) one get's, x = 45, y = 15
? A's age = 45 years
B's age = 15 years
? Difference of their ages = 45 - 15 = 30 years
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