Let the present age of father be x years and the sum of present ages of 2 sons be y years.
? x = 3y ...(i)
? (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]
Solving (i) and (ii), we get
x = 30 years
Let son's present age be x years and father's age = (45 - x) years.
? (x - 5) (45 - x - 5) = 4 ( 45 - x - 5)
? (40 - x) (x - 9) = 0
? x = 9years
? The son's age = 9 years
Father's age = 45 - 9 = 36 years
? Anup's age = (5 - 2) years = 3 years
Let Randheer's age be x years.
Then, (x - 6)/18 = 3
? x = 54 + 6 = 60
Let son's age present age be x years .
? Father's present age = 3x years
Son's age 10 years hence = ( x + 10) years
Father's age 10 years hence = (3x + 10)
As per the condition ,
? ( x + 10) + (3x + 10) = 76
? 4x = 56
? x = 14
? Son's present age = 14 years
Father's present age = 42 years
Let the age of Mona and her mother be 5x and 13x years respectively.
Then, (13x - 5x) = 24
? x = 3
So, their present ages are 15 years and 39 years
Ratio of their ages after 3 years = 18 : 42 = 3 : 7
Let Kamla's age 6 years ago be x years.
So, Kamla's present age = (x + 6) years
? x + 6 = 5x / 4
? 4x + 24 = 5x
? x = 24
So, Kamla's Present age = (x + 6) years = 30 years
? Son's present age = 30/10 = 3 years
Let the average age of A, B and C be N years.
? Total age of A, B and C = 3 x N = 3N years
Now, according to the question,
? 3N - (2N + N/2) = 5
? N = 10 years.
Let the mother's age 2 years ago be 4x and daughter's age 2 years ago be be x.
? (4x + 8) - (x + 8) = 12
? 3x = 12
? x = 4
? Mother's present age = 4x + 2 = 18 years
and daughter's present age = x + 2 = 6 years
? Required ratio = 3 : 1
Let the present age of the son be x and that of the father be 4x years.
? (x - 5) + (4x - 5) = 60
? 5x = 70
? x = 14 years
? Father's present age = 4x = 56 years
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
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