Let A's age 10 years ago = x years
Then, B's age 10 years ago = 2x years
? (x + 10) / (2x + 10) = 3 / 4
? 4(x + 10) = 3(2x + 10)
? x(6 - 4) = 40 - 30
? x = 5
&ther4; Total of their present ages = (x + 10) + (2x + 10)
= (3x + 20)
= 35 years
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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