? 3x + 5x = 80
? x = 10
Ratio of their ages after 10 years = (3x + 10) : (5x + 10) = 40 : 60 = 2 : 3
Let the son's present age be x years
Then, (x + 4) + (4x + 4) = 43
? 5x = 35
? x = 7
Let father's age be 4T and son's age T years.
? 4T x T = 196
? T2 = 49
? T = 7
Father's age after 5 years = (4T + 5) = 33 years
Son's age after 5 years = (T + 5) = 12 years
? Ratio of their ages after 5 years = 33 : 12 = 11 : 4
Total speed of car, bus and train = 72 × 3 = 216 Km
Speed of car and train = ( 5 + 9 ) x 216 / ( 5 + 9 + 4 ) = 168 Km
Average = 168 / 2 = 84 Km
A : B : C = 90 : 75 : 60
B:C = 75 / 60 = ( 75 x 100?75 ) / ( 60 x 100?75) = 100 / 80
Hence, in a game of 100 points, B can give C(100 - 80)
= 20 points.
A scores 100 while B scores 100 - 20 = 80 and C scores 100 - 28 = 72.
? While B scores 80, C scores 72.
? While B scores 100, C scores 72 × 100 / 80 = 90.
? B can give C 100 - 90 = 10 points.
Let Ashok's age = 4x years and Pradeep's age = 3x years
From question, 4x + 6 = 26
? x = 5
&ther4; Pradeep's age = 3x = 15 years.
Let Ajay's age 10 years back be x years.
Then Sachin's age 10 years back = 2x years
? 2x + 20 = 40
? x = 10
? Present age of Ajay = x + 10 = 20 years
Let the son's present age be x years
Then, (x + 4 ) + (4x + 4) = 43
? 5x = 35
? x = 7 years
Let the age of B be N years
According to the question
? N + 20 = 6N
? N = 4 years
? A's age = 4 x 6 = 24 years and B's age = 4 years
Suppose x years later the father will be twice as old as his son.
? x + 41 = 2 (x + 16)
? x = 41 - 32 = 9 years
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