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- Question
- A runs 1 2/ 3 times as fast as B. If A gives B a start of 40 m, how far must the winning post be, so that A and B might reach it at the same time?
Options- A. 75 m
- B. 200 m
- C. 100 m
- D. 125 m
- Correct Answer
- 100 m
ExplanationRatio of the speeds of A and B = 5 : 3
Thus, in a race of 5m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
40 m will be gained by A in a race of (5/2) x 40 m = 100 m
? Winning post is 100 m away from the starting point. - 1. A 10 km race is organised at 800 m circular race course. P and Q are the contestants of the race. If the ratio of the speed of P and Q is 5 : 4, how many times will the winner overtake the loser?
Options- A. 4 times
- B. 1 times
- C. 2 times
- D. 3 times Discuss
- 2. A, B and C walk 1 km in 5 min, 8 min and 10 min, respectively, C starts walking from a points at a certain time, B starts from the same point 1 min later and A starts from the same
point 2 min later than C, Then, A meet B and C at times?
Options- A. 2 min, 3 min
- B. 4/3 min, 3 min
- C. 2 min, 5/3 min
- D. 1 min, 2 min Discuss
- 3. Arun and Bhaskar start from place P at 6:00 am and 7:30 am, respectively and run in the same direction. Arun and Bhaskar run at 8 km/h and 12 km/h. respectively. Bhaskar overtakes
Arun at?
Options- A. 10 : 30 am
- B. 9 : 00 am
- C. 11 : 30 am
- D. 1 : 00 am Discuss
- 4. In a game of billiards, A can give B 20 points in the game of 120 points and he can give C 30 points in the game of 120 points, How many points can B give C in a game of 90?
Options- A. 9 points
- B. 18 points
- C. 6 points
- D. 3 points Discuss
- 5. A can run a distance of 1 Km in 3 minutes 10 seconds and B can run the same distance in 3 minutes 20 seconds. If they start together, by what distance will A beat B?
Options- A. 50 m
- B. 30 m
- C. 36 m
- D. 60 m Discuss
- 6. In a 20 m race, A runs at a speed of 2 m/s. If A gives B a start of 10 m and still beats him by 5 s, what will be the speed of B?
Options- A. 117/21 m/s
- B. 317/21 m/s
- C. 21 m/s
- D. 2 m/s Discuss
- 7. Shantanu started cycling along the boundaries of a square field ABCD from corner point A. After 1/2 h, he reached the corner point C, diagonally opposite to point A. If his speed was 16 km/h. Find the area of the field?
Options- A. 8 sq km
- B. 9 sq km
- C. 19 sq km
- D. None of the above Discuss
- 8. In a race of 800 meter, A can beat B by 40 meter. In a race of 500 meter, B can beat C by 5 meter. In a race of 200 meter, A will beat C by
Options- A. 12.7 m
- B. 11.9 m
- C. 1.27 m
- D. 1.19 m Discuss
- 9. Three men Ram, Karan and Mohan run around an oval garden from a fixed post at the rates of 5, 5 1? 7, 5 1? 3 per hour. They come back to the fixed post in 3 3? 4 hours. Find the greatest length, the race course can have.
Options- A. 28 / 5 km
- B. 5 / 28 km
- C. 11 / 28 km
- D. 28 / 11 km Discuss
- 10. A and B start from the same point and travel in the same direction round a circular track 3 km in circumference. If their speed be 200 and 150 metres a minute, when will they first together again at the starting point?
Options- A. 40 min
- B. 55 min
- C. 1 hour
- D. 45 min Discuss
Races and Games problems
Search Results
Correct Answer: 2 times
Explanation:
Speed of P : Speed of Q = 5 : 4
Time taken by P to cover 5 rounds = Time taken by Q to cover 4 rounds
Distance covered by P in 5 rounds = 5 x (800/1000) = 4 km
Distance covered by Q in 4 rounds = 4 x (800/1000) = 16/5 km
In 5 rounds, P will overtake Q every time. It means that after covering 4 km, P will overtake Q one time .
? After covering 10 km P will overtake Q, = (1/4) x 10 = 21/2 times
Correct Answer: 2 min, 5/3 min
Explanation:
A walks 1 km in 5 min.
Then, distance covered by A in 1 min = 1000/5 = 200 m
B walks 1 km in 8 min.
Then, distance covered by B in 1 min = 1000/8 = 125 m
C walks 1 km in 10 min.
Then, distance covered by C in 1 min = 1000/101 = 100 m
Let A meets B and C in x and y min, respectively.
Then, according to the question,
Distance covered by C in(x + 2) min = Distance covered by A in x min
? 100(x + 2) = 200 x
?100 x + 200 = 200 x
? 200 = 100 x
? x = 200/100 = 2 min
Now, for A and B
Distance covered by B in (y + 1) min = Distance covered by A in y min
? 125(y + 1) = 200y
? 125y + 125 = 200y
? 125 = 200y - 125y
? 125 = 75y
? y = 125/75 = 5/3 min.
Correct Answer: 10 : 30 am
Explanation:
Distance between Arun and Bhaskar at 7:30 am = 8 x 11/2 = 12 km
Time taken by Bhaskar in covering a distance of 12 km = 12/(12 - 8) = 3 h
? Required time = 10 : 30 am
Correct Answer: 9 points
Explanation:
If A scores 120 points, then B scores 100 points and C scores 90 points.
When B scores 100 points, then C scores 90 points.
When B scores 90 points than C scores (90/100) x 90 points = 81 points
? B can give C, 9 points in a game of 90.
Correct Answer: 50 m
Explanation:
According to question,
A can run a distance of 1 Km in 3 minutes 10 seconds and B can run the same distance in 3 minutes 20 seconds.
A beats B by 10 sec.
So distance covered by B in 10 sec. = (1000 *10 / 200) m = 50 m
? A beat B by 50 m.
Correct Answer: 117/21 m/s
Explanation:
Time taken by A to cover 200 m = 200/2 = 100 s
? B covers (200 - 10) = 190 m in (100 + 5) = 105 s
? B' s speed = 190/105 = 38/21 = 117/21 m/s
Correct Answer: None of the above
Explanation:
Distance = (AB + BC) = 2L = 16 x 1/2 = 8 km
? L = 8/2 = 4 km
? Area of the field = 4 x 4 = 16 sq km.
Correct Answer: 11.9 m
Explanation:
In a 800 meter race, A covers 800 meter while B cover 760 meter.
? A covers 200 m while B will cover 760 x 200 / 800 = 190 m
Again, B covers 500 m while C 495 m
? B covers 190 m while C will cover = 495 x 190 / 500 = 188.10 m
Since, A covers 200 m while C 188.10 m
Hence, A will beat C by (200 ? 188.10) = 11.9 m
Correct Answer: 5 / 28 km
Explanation:
Total number of rounds made by Ram in 15 / 4 hrs = 5 × 15 / 4 = 75 / 4
? Total number of rounds made by Karan in 15 / 4 hrs = 36 / 7 * 15 / 4 = 135 / 7
Total number of rounds made by Mohan in 15 / 4 hrs = 16 / 3 * 15 / 4 = 20
H.C.F. of 75 / 4 , 135 / 7 and 2 = 5 / 28
Correct Answer: 1 hour
Explanation:
Time taken by A in one round = 3000 / 200 = 15 min.
Time taken by B in one round = 3000 / 150 = 20 min
L.C.M. of 15 min and 20 min = 60 min = 1 hr.
Hence, they will meet first together at the starting point after 1 hour.
2nd Method to solve this
Let us assume after T minutes both A and B will meet first time together at starting points.
According to question,
Distance covered by A in T minutes = 200 x T = 200T
Distance covered by B in T minutes = 150 x T = 150T
200T - 150T = 3000 As we know (3 KM = 3000 meters)
? 50T = 3000
? 5T = 300
? T = 300/5 = 60 Minutes.
As we know ( 60 minutes = 1 hours)
? T = 1 Hours
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