If A scores 120 points, then B scores 100 points and C scores 90 points.
When B scores 100 points, then C scores 90 points.
When B scores 90 points than C scores (90/100) x 90 points = 81 points
? B can give C, 9 points in a game of 90.
According to question,
A can run a distance of 1 Km in 3 minutes 10 seconds and B can run the same distance in 3 minutes 20 seconds.
A beats B by 10 sec.
So distance covered by B in 10 sec. = (1000 *10 / 200) m = 50 m
? A beat B by 50 m.
While Arun's 1000 m, B runs 1000 - 100 = 900 m and C runs 1000 - 200 = 800 m.
? While B runs 900 m, C runs 800 m.
? While B runs 1350 m; C runs 800 / 900 × 1350 = 1200 m
? B can beat C by 1350 - 1200 = 150 m.
Time taken by A to cover 100 meters
= 100 ÷ (5 * 5 / 18) = 72 seconds.
? B covers (100 - 8) or, 92 meters in (72 + 8) or, 80 seconds.
? Speed of B = ( 92 / 80 ) * ( 16 / 5 ) = 4.14 Km/h.
Time taken by Kamal to run 100 m = 100 / 18 x 5 / 18 = 20 s Therefore, time taken by Bimal to run 100 m = 20 + 5 = 25 s
Hence, Bimal's speed = 100 / 25 = 4 m/sec = 4 x 18 Km/h = 14.4 Km/h
A will reach at starting point in 5 * 2 / 5 = 2 hours ;
B will reach at starting point in 5 / 3 hours ;
C will reach at starting point in 5 / 2 hours ;
Then, on the starting point all three will meet after the L.C.M. of 2, 5 / 3, 5 / 2, 10 / 1 = 10 hours.
Distance between Arun and Bhaskar at 7:30 am = 8 x 11/2 = 12 km
Time taken by Bhaskar in covering a distance of 12 km = 12/(12 - 8) = 3 h
? Required time = 10 : 30 am
A walks 1 km in 5 min.
Then, distance covered by A in 1 min = 1000/5 = 200 m
B walks 1 km in 8 min.
Then, distance covered by B in 1 min = 1000/8 = 125 m
C walks 1 km in 10 min.
Then, distance covered by C in 1 min = 1000/101 = 100 m
Let A meets B and C in x and y min, respectively.
Then, according to the question,
Distance covered by C in(x + 2) min = Distance covered by A in x min
? 100(x + 2) = 200 x
?100 x + 200 = 200 x
? 200 = 100 x
? x = 200/100 = 2 min
Now, for A and B
Distance covered by B in (y + 1) min = Distance covered by A in y min
? 125(y + 1) = 200y
? 125y + 125 = 200y
? 125 = 200y - 125y
? 125 = 75y
? y = 125/75 = 5/3 min.
Speed of P : Speed of Q = 5 : 4
Time taken by P to cover 5 rounds = Time taken by Q to cover 4 rounds
Distance covered by P in 5 rounds = 5 x (800/1000) = 4 km
Distance covered by Q in 4 rounds = 4 x (800/1000) = 16/5 km
In 5 rounds, P will overtake Q every time. It means that after covering 4 km, P will overtake Q one time .
? After covering 10 km P will overtake Q, = (1/4) x 10 = 21/2 times
Ratio of the speeds of A and B = 5 : 3
Thus, in a race of 5m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
40 m will be gained by A in a race of (5/2) x 40 m = 100 m
? Winning post is 100 m away from the starting point.
Time taken by A to cover 200 m = 200/2 = 100 s
? B covers (200 - 10) = 190 m in (100 + 5) = 105 s
? B' s speed = 190/105 = 38/21 = 117/21 m/s
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