Speeds (in m/sec) of A and B are
9 / 2 * 5 / 18 = 5 / 4 and 6 * 5 / 18 = 5 / 3, respectively.
A has a start of 190 m.
So, A has to run 1000 - 190 = 810 m, while B 1000 m.
Time taken by B to cover 1000 m = 3 5 × 1000 = 600 seconds.
In this time, A covers 5 × 600 / 4 = 750 m.
So, B reaches the winning post while A remains 810 - 750 = 60 m behind.
? B wins by 60 m.
Distance covered = 550 meter. = 0.55 km
Speed of the train = 55 km/hr
So time taken = 0.55 / 55 =1/100 hr = (60 x 60 )/100 sec = 36 sec
? = 953.7 ÷ 950.9989 = 95?
? 95(3.7 - 0.9989) = 95?
? 952.7011 = 95?
? ? = 2.7011 ? 2.7
❨ | √625 | x | 14 | x | 11 | ❩ | is equal to: |
11 | √25 | √196 |
Given Expression = | 25 | x | 14 | x | 11 | = 5. |
11 | 5 | 14 |
Time = | ❨ | 100 x 81 | ❩years | = 4 years. |
450 x 4.5 |
Therefore x = 21%
Total no.of boys : no. of girls = 13:27
27 : 13
Let the price of the mixed variety be Rs. x per kg. By the rule of alligation, we have :
Cost of 1 kg of type 1 rice Cost of 1 kg of type 2 rice
(20-x)/(x-15) = 2/3
60 - 3x = 2x - 30
x = 18.
pool : kerosene
3 : 2(initially)
2 : 3(after replacement)
(for petrol)
=> K = 30
Therefore the total quantity of the mixture in the container is 30 liters.
Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.
The capacity of the pot is 44 liters.
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