Speed downstream = (5 + 1) km/hr = 6 km/hr
Speed upstream = (5 - 1) km/hr = 4 km/hr
Let the required distance be d km
Then, d/6 + d/4 = 1
? 2d + 3d = 12
? d = 2.4 km
Speed downstream = (28/5) km/hr = 5.6 km/hr
Speed upstream = (16/5) km/hr = 3.2 km/hr
Velocity of current = (5.6 - 3.2)/2 km/hr = 1.2 km/hr
Speed upstream = 6 km/hr
Speed downstream = 10 km/hr
? Speed of the current = (10 - 6)/2 km/hr = 2 km/hr
Let the speed in still water be x km/hr
Then, 6/x + 4 + 6/x - 4 = 2
? 6[ x - 4 + x + 4] = 2(x2 - 16)
? x2 - 6x - 16 = 0
? (x - 8) (x + 2) = 0
? x = 8 km/hr
? (12 x 60)/48 = (L - 2)
? L = 15 + 2 = 17 km/hr
Downstream speed of boat = Speed of boat in still water + Speed of stream
= 24 + 8 = 32 km/h
? Required time = Distance/Speed downstream
= 128/32 = 4 km/h
? Man's rate in still water = (man's rate with current + his rate against current)/2
? 8 = 1/2 [ 44/4 + 25/T ]
? 16 = 11 + 25/T
? T = 5 hours
Rate downstream = 48/8 = 6 km/hr
Rate upstream = 48/12 = 4 km/hr
? Speed of boat in still water = (6 + 4)/2 = 5 km/hr
Rate of stream = (6 -4)/2 = 1 km/hr
Downstream speed = 60/6 = 10 km/hr
Speed of stream = 3 km/hr
Upstream speed = 10 - (2 x 3) = 4 km/hr
? Required time = 16/4 = 4 hours.
Upstream speed = 7 - 1.5 = 5.5 km/hr
? 5.5 x T = 7.7
? T = 77.7 / 5.5 = 1hr. 24 minutes
Let speed of the flow of water be x km/h and rate of sailing of sailor be y km/h.
Downstream speed (x + y) = 48/8
? x + y = 6 ....(i)
and upstream speed x - y = 4 ...(ii)
On solving Eqs. (i) and (ii), we get
y = 1 km/h
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