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- Question
- The banker's discount on Rs. 1650 due a certain time hence is Rs. 165. Find the true discount and the banker's gain?
Options- A. Rs. 150, Rs. 15
- B. Rs. 160, Rs. 5
- C. Rs. 145, Rs. 20
- D. None of these
- Correct Answer
- Rs. 150, Rs. 15
ExplanationSum = (B.D. x T.D.) / (B.D. - T.D.) = (B.D. x T.D.) / B.G.
? T.D. / B.G. = Sum / B.D. = 1650/165 = 10/1
i.e., if B.G. is Re. 1, T.D. = Rs. 10 or B.D. = Rs. 11
? if B.D. is Rs. 11, T.D. = Rs. 10
If B.D. is Rs. 165, T.D. = Rs. (10/11) x 165 = Rs. 150
Also, BG = Rs. (165 - 150) = Rs. 15 - 1. A rectangular courtyard 3.78 meters long 5.25 meters wide is to be paved exactly with square tiles, all of the same size. what is the largest size of the tile which could be used for the purpose?
Options- A. 14 cms
- B. 21 cms
- C. 42 cms
- D. None of these Discuss
- 2. The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 is :
Options- A. 49/7
- B. 19/7
- C. 50/7
- D. 18/7 Discuss
- 3. A certain sum is invested for 2 years in scheme M at 20% p.a. compound interest (compounded annually), Same sum is also invested for the same period in scheme N at k% p.a. simple interest. The interest earned from scheme M is twice of that earned from scheme N. What is the value of k?
Options- A. 7
- B. 11
- C. 9
- D. 13 Discuss
- 4. What is the area (in square units) of the figure enclosed by the graphs of the lines x = -4, x = 2, y = -2 and y = 3?
Options- A. 12
- B. 24
- C. 15
- D. 60 Discuss
- 5. If the length of the side of an equilateral triangle is 8 cm, what is its area?
Options- A. 32?3 sq cm
- B. 16 sq cm
- C. 16?3 sq cm
- D. 32 sq cm Discuss
- 6. If logxl+m-2n = logym+n-2l = logzn+l-2m , then xyz is equal to
Options- A. 0
- B. 1
- C. lmn
- D. 2 Discuss
- 7. What is the average of first 7 multiples of 7?
Options- A. 7
- B. 14
- C. 28
- D. 21 Discuss
- 8. Square units 13 by 9 of an office area is
Options- A. 97
- B. 117
- C. 107
- D. 127 Discuss
- 9. An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metre of cloth ?
Options- A. 194 seconds
- B. 195 seconds
- C. 196 seconds
- D. 197seconds Discuss
- 10. The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
Options- A. 333 sq.mts
- B. 330 sq.mts
- C. 362 sq.mts
- D. 432 sq.mts Discuss
More questions
Correct Answer: 21 cms
Explanation:
3.78 meters =378 cm = 2 × 3 × 3 × 3 × 7
5.25 meters=525 cm = 5 × 5 × 3 × 7
Hence common factors are 3 and 7
Hence LCM = 3 × 7 = 21
Hence largest size of square tiles that can be paved exactly with square tiles is 21 cm.
Correct Answer: 18/7
Correct Answer: 11
Explanation:
Interest earned in scheme M =
Interest earned in scheme N =
Now, from the given data,
k = 11
Correct Answer: 15
Correct Answer: 16?3 sq cm
Correct Answer: 1
Correct Answer: 28
Correct Answer: 117
Explanation:
Square units 13 by 9 of an office means office of length 13 units and breadth 9 units.
Now its area is 13x 9 = 117 square units or units square.
Correct Answer: 195 seconds
Explanation:
Let the time required by x seconds.
Then, More cloth means More time (Direct Proportion)
So, 0.128 : 1 :: 25 : x
=> x = 195.31
So time will be approx 195 seconds
Correct Answer: 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
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