Here, A = 2/5, R = 15%
According to the formula
Gain % = AR/(1 - A)%
= [(2/5) x 15]/[1 - (2/5)]%
= (6 x 5)/3%
= 10%
We know that, when the trains are moving in the same direction,
Relative speed= Difference between the speed of train
and total distance for crossing each other = Sum of the length of train
Therefore, Relative speed = 72 km/hr - 54 km /hr = 18 km/hr
Relative speed in m/sec = 18 km/hr x 5/18 = 5 m/sec
and Total distance = 200m + 300m = 500m
and Total time taken to cross each other = Total distance in meter/ Relative speed in m/sec
= 500 m / (5 m/sec) = 100 sec
Then, 14x : 8y : 7z = 5 : 7 : 8.
Now, | 14x | = | 5 | ⟺ 98x = 40y ⟺ y = | 49 | x |
8y | 7 | 20 |
And, | 14x | = | 5 | ⟺ 112x = 35z ⟺ z = | 112 | x = | 16 | x. |
7z | 8 | 35 | 5 |
∴ x : y : z = x : | 49 | x | : | 16 | x | = 20 : 49 : 64. |
20 | 5 |
Original area = (xy) m2.
New length = | ❨ | 120 | x | ❩m | = | ❨ | 6 | x | ❩m. |
100 | 5 |
New breadth = | ❨ | 120 | y | ❩m | = | ❨ | 6 | y | ❩m. |
100 | 5 |
New Area = | ❨ | 6 | x x | 6 | y | ❩m2 | = | ❨ | 36 | xy | ❩m2. |
5 | 5 | 25 |
The difference between the original area = xy and new-area 36/25 xy is
= (36/25)xy - xy
= xy(36/25 - 1)
= xy(11/25) or (11/25)xy
∴ Increase % = | ❨ | 11 | xy x | 1 | x 100 | ❩% | = 44%. |
25 | xy |
Quantity of milk = | ❨ | 60 x | 2 | ❩litres = 40 litres. |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ❨ | 40 | ❩ | . |
20 + x |
Now, | ❨ | 40 | ❩ | = | 1 |
20 + x | 2 |
⟹ 20 + x = 80
⟹ x = 60.
∴ Quantity of water to be added = 60 litres.
Let the original number of men = N
Time taken by N = 80 days
Now, (N - 10) men can finish the work in the (80 + 20) = 100 days
Here, M1 = N, M2 = (N - 10), D1 = 80 and D2 = 100
According to the formula.
M1D1 = M2D2
? N x 80 = 100 x (N - 10)
? 8N = 10N - 100
? 10N - 8N = 100
? N = 50
No. of pieces = Total length / Length of each piece
= 192/3.2
= 60
Let the amount instalment be Rs ' x '
Then According to question,
(Amount of 'x' for 3 yrs) + (Amount of 'x' for 2 yrs) + (Amount of 'x' for 1 yrs) + x =3220
or, [x+(x × 10 × 3)/100] + [x+(x × 10 × 2)/100] + [x+(x × 10 × 1)/100] + x=3220
? 4x+ (30x/100)+(20x/100)+(10x/100)=3220
? 460x=322000
? x=Rs 700
? Each Instalment= Rs 700
Let the daughter's present be x years.
Then, mother's present age = (50 - x) years
Now, 7(x -5) = (50 - x - 5)
? x = 10
So, the present ages of mother and daughter are 40 years and 10 years respectively.
27 is in the middle, so is the median and its the mean too.
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