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- Question
- Two trains running in opposite directions cross a man standing on the platform 54s and 34s respectively and they cross each other in 46 s . Find the ratio of their speeds.?
Options- A. 3 : 2
- B. 2 : 3
- C. 5 : 3
- D. 3 : 5
- Correct Answer
- 3 : 2
ExplanationLet the speeds of two trains be x and y, respectively .
? Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46
? 54x + 34y = 46x + 46y
? 27x + 17y = 23x + 23y
? 4x = 6y
? x/y = 3/2
? x : y = 3 : 2 - 1. Without stoppages, the speed of a train is 150 km/h and with stoppages, it is 100 km/h. How many minutes does the train stop?
Options- A. 20
- B. 15
- C. 25
- D. 45 Discuss
- 2. Excluding stoppages, the speed of a train is 108 km/h and including stoppages, it is 90 km/h. For how many minute does the train stop per hour?
Options- A. 5
- B. 9
- C. 10
- D. 6 Discuss
- 3. From station M and N, two trains start moving towards each other at speed 125 km/h and 75 km/h, respectively. When the two trains meet each other, it is founds that one train covers 50 km more than another. Find the distance between M and N.?
Options- A. 190 km
- B. 200 km
- C. 145 km
- D. 225 km Discuss
- 4. The ratio between the speeds of two train is 8 : 9 Second train covers 360 km in 4 h. Distance covered by first train in 3 h (in km ) is?
Options- A. 240
- B. 480
- C. 120
- D. 60 Discuss
- 5. Two train start at the same time from points x and y towards each other and after crossing, they take 9 h and 4 h in reaching points y and x, respectively. Find the ratio of speeds of the 1st train to that of the 2nd train?
Options- A. 2 : 3
- B. 3 : 2
- C. 2 : 5
- D. 5 : 3 Discuss
- 6. Two trains are running 40 km/h and 20 km/h respectively, in the same directions. The fast train completely passes a man sitting in the slow train in 5 s. The length of the fast a train is?
Options- A. 232/9 m
- B. 27 m
- C. 277/9 m
- D. 23 m Discuss
- 7. Two trains of same length take 6 s and 9 s, respectively to cross a pole. If both the trains are running in the same direction, then how long will they take to cross each other?
Options- A. 30 s
- B. 36 s
- C. 40 s
- D. 42 s Discuss
- 8. P and Q are 27 km away. Two trains will having speeds of 24 km/h and 18 km/h respectively starts simultaneously from P and Q and travel in the same direction. They meet at a point R beyond Q. Distance QR is
Options- A. 126 km
- B. 81 km
- C. 48 km
- D. 36 km Discuss
- 9. Two station P and Q are at a distance of 160 km. Two trains starts moving from P and Q to Q and P respectively and meet each other after 4 h . If speed of the train starting from P is more than that of other train by 6 km/h. then find the speeds of both the trains, respectively.?
Options- A. 19 km/h, 13 km/h
- B. 13 km/h, 9 km/h
- C. 17 km/h, 23 km/h
- D. 16 km/h, 10 km/h Discuss
- 10. A train leaves Mumbai for Goa at 3:45 pm and goes at the rate of 50 km/h. Another train leaves Goa for Mumbai at 2:35 pm and distance between Mumbai and Goa is 510 km. at what distance from Mumbai will the two trains meet?
Options- A. 200 km
- B. 150 km
- C. 145 km
- D. 300 km Discuss
Problems on Trains
Search Results
Correct Answer: 20
Explanation:
Because of stoppages, train covers 50 km less per hour.
? Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 min
Correct Answer: 10
Explanation:
Because of stoppages, train covers 18 km less per hour .
? Time taken to cover 18 km = 18/108 = 1/6 h = (1/6) x 60 = 10 min
Correct Answer: 200 km
Explanation:
Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)
For station M,
(x + 50) = 125t
? x = 125t - 50 ..(i)
For station N,
x = 75t .....(ii)
From Eqs. (i) and (ii), we get
75t = 125t - 50
? t = 1h
Distance between station M and N = 125 + 75t = 200 x 1 = 200 km
Correct Answer: 240
Explanation:
Let speed of 1st train be 8S and speed of 2nd train be 9S
According to the question.
Speed of second train = 360/4 = 90 km/h
9S = 90
? S = 10
So, speed of 1st train = 8 x 10 = 80 km/h
? Required distance = 80 x 3 = 240 km
Correct Answer: 2 : 3
Explanation:
Given that, T1 = 9 h and T 2 = 4 h
According to the formula.
(1st train's speed) : (2nd train's speed) = ?4 : ?9
= 2 : 3
Correct Answer: 277/9 m
Explanation:
The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5 = 277/9 m
Correct Answer: 36 s
Explanation:
Given that, t1 = 6 s and t2 = 9 s
Then, time taken by the trains to cross each other = 2t1 t2 / (t2 - t1)
= (2 x 6 x 9)/(9 - 6) = 36 s
Correct Answer: 81 km
Explanation:
If the trains meet after t h.
Relative speed of train = (24 -18) = 6 km/h
? Distance = 27
? t = 27/6 = 9/2 h
? QR distance travel by train which is travelling at a speed of 18 km/h = 18t = 18 x 9/2 = 81 km
Correct Answer: 17 km/h, 23 km/h
Explanation:
Let the speed of both trains be V km/h and (V + 6) km/h, respectively
Then, according to the question.
160 = V x 4 + (V + 6) x 4
? 160 = 4V + 4V + 24
? 40 = V + V + 6
? 2V + 6 = 40
? 2V = 34
? V = 17
Hence, speeds of both the trains are 17 km/h and (17 + 6 ) km/h i,e 17 km/h and 23 km/h .
Correct Answer: 200 km
Explanation:
Let the two trains meet at D km from Mumbai. Then,
3:45 pm + D/50 = 2 : 35 pm + 510 - D/60
? (3:45 pm - 2:35 pm) + (D/50 + D/ 60) = 510/60
? (11/6 h) + D{( 50 + 60 / 50 x 60)} = 17/2
? D(110/3000) = 17/2 - 7/6
? D(110/3000) = (51 - 7)/6 = 44/6
? D = (44/6) x (3000/110) = 200 km
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