Because of stoppages, train covers 50 km less per hour.
? Time taken taken to cover 50 km = 50/150 h = (50/150) x 60 = 20 min
Because of stoppages, train covers 18 km less per hour .
? Time taken to cover 18 km = 18/108 = 1/6 h = (1/6) x 60 = 10 min
Let the trains meet after time t at a distance x from station N.
Then another train coming from station M covers a distance of (x + 50)
For station M,
(x + 50) = 125t
? x = 125t - 50 ..(i)
For station N,
x = 75t .....(ii)
From Eqs. (i) and (ii), we get
75t = 125t - 50
? t = 1h
Distance between station M and N = 125 + 75t = 200 x 1 = 200 km
Let speed of 1st train be 8S and speed of 2nd train be 9S
According to the question.
Speed of second train = 360/4 = 90 km/h
9S = 90
? S = 10
So, speed of 1st train = 8 x 10 = 80 km/h
? Required distance = 80 x 3 = 240 km
Given that, T1 = 9 h and T 2 = 4 h
According to the formula.
(1st train's speed) : (2nd train's speed) = ?4 : ?9
= 2 : 3
Let length of each train be L m.
Then. (65 + 85 ) x 5/18 = (L + L)/6
? (150 x 5 x 6)/18 = 2L
? 2L = 250
? L = 125 m
Let the speeds of two trains be x and y, respectively .
? Length of 1st train = 54x
Length of the 2nd train = 34y
According to the question.
(54x + 34y) / (x + y) = 46
? 54x + 34y = 46x + 46y
? 27x + 17y = 23x + 23y
? 4x = 6y
? x/y = 3/2
? x : y = 3 : 2
The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5 = 277/9 m
Given that, t1 = 6 s and t2 = 9 s
Then, time taken by the trains to cross each other = 2t1 t2 / (t2 - t1)
= (2 x 6 x 9)/(9 - 6) = 36 s
If the trains meet after t h.
Relative speed of train = (24 -18) = 6 km/h
? Distance = 27
? t = 27/6 = 9/2 h
? QR distance travel by train which is travelling at a speed of 18 km/h = 18t = 18 x 9/2 = 81 km
Let the speed of both trains be V km/h and (V + 6) km/h, respectively
Then, according to the question.
160 = V x 4 + (V + 6) x 4
? 160 = 4V + 4V + 24
? 40 = V + V + 6
? 2V + 6 = 40
? 2V = 34
? V = 17
Hence, speeds of both the trains are 17 km/h and (17 + 6 ) km/h i,e 17 km/h and 23 km/h .
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