Total distance = 130 m = 0.13 km
Speed of the train = 40 km /hr
Time taken = 0.13/40 hr = (0.13 x 60 x 60) / 40 = 11.7 sec.
Distance covered in 72 sec. = 300 + 900 m
? Speed = 1200/72 = 50/3 m/sec. = 60 km/hr .
Relative speed of both trains = (32 + 40) = 72 km/hr = 72 x (5/18) = 20 m/sec
Distance covered in crossing each other = 132 + 108 = 240 m
? Required time = 240/20 = 12 sec.
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
Let the length of train = L metres
Speed of train = 45 x (5/18) = 25/2 m/sec.
Distance covered in crossing the platform = (L + 100) m
? (L + 100) x (2/25) = 60
? 2L + 200 = 1500
? L = 650.
Now, time taken to cross the pole = 650 x (2/25) = 52 sec.
speed of train = 36 x (5/18) = 10 m/sec.
Let the length of the train be L meters
Then, L/10 = 10
? L = 100 meters.
? Time taken to cross the platform = (100 + 55) / 10 = 151/2 sec.
Speed = 30 km/hr = 30 x (5/18) = 25/3 m/sec.
? Length of the train = (25/3) x (27/2)
= 225/2 = 1121/2 metres
Speed of the train = (160/18) x (18/5) = 32 km/hr.
Speed of the train = 45 km/hr = 45 x (5/18) = 25/2 m/sec
Let the length of the bridge be L metres
? (L + 130) / (25/2) = 30
? L + 130 = 15 x 25
L = 375 - 130 = 245 metres
Speed of the column of men = (50 x 75) / (100 x 60) = 5/8 m/sec.
Let the length of the street be L metres
? (L + 250) = (60 x 60 x 5) / 8 = 2250 metres
? L = (2250 - 250) m
? L = 2000 m = 2 km.
? Speed of the train = 72 km/hr = 72 x (5/18) = 20 m/sec.
Sum of the length of the train and tunnel = 540 + 160 = 700 metres.
? Required time taken to pass the tunnel = Time taken to cover 700 metres at 20 m/sec.
= 700/20
= 35 sec.
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