Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
? 4(798 X 579) / (798 X 579)
? 4
x : y = 8 : 15
If y = 10, x = 8/15 X 10
y = 16/3
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