Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
Let the length of train = L metres
Speed of train = 45 x (5/18) = 25/2 m/sec.
Distance covered in crossing the platform = (L + 100) m
? (L + 100) x (2/25) = 60
? 2L + 200 = 1500
? L = 650.
Now, time taken to cross the pole = 650 x (2/25) = 52 sec.
speed of train = 36 x (5/18) = 10 m/sec.
Let the length of the train be L meters
Then, L/10 = 10
? L = 100 meters.
? Time taken to cross the platform = (100 + 55) / 10 = 151/2 sec.
Relative speed of both trains = (150 + 100)/10 = 25 m/sec = 25 x (18/5) = 90 km/hr
? Speed of second train = (90 - 30) = 60 km/hr .
? Relative speed of the train = (40 - 25) km/hr = 15 x (5/18) = 25/6 m/sec
? Length of the train = (48 x 25) / 6 = 200 meters .
Let the speed of the train be v km/hr
Relative speed of the train = (v + 6) km/hr = [(v + 6) x 5/18] m/sec
? 150/6 = (v + 6) x (5/18)
? 5v + 30 = 450
? v = 84 km/hr
Relative speed of both trains = (32 + 40) = 72 km/hr = 72 x (5/18) = 20 m/sec
Distance covered in crossing each other = 132 + 108 = 240 m
? Required time = 240/20 = 12 sec.
Distance covered in 72 sec. = 300 + 900 m
? Speed = 1200/72 = 50/3 m/sec. = 60 km/hr .
Total distance = 130 m = 0.13 km
Speed of the train = 40 km /hr
Time taken = 0.13/40 hr = (0.13 x 60 x 60) / 40 = 11.7 sec.
Speed = 30 km/hr = 30 x (5/18) = 25/3 m/sec.
? Length of the train = (25/3) x (27/2)
= 225/2 = 1121/2 metres
Speed of the train = (160/18) x (18/5) = 32 km/hr.
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