Let the speed of the second train be y km/hr
Relative speed of both trains = (50 + y) km/hr
Total distance traveled = 100 + 120 = 220 meters = 0.22 km
Time = 6 sec = 6/( 60 x 60) hr.
Speed = distance/time
? 50 + y = (0.22 x 60 x 60)/ 6
? 50 + y = 132
? y = 82
? Speed of the second train = 82 km/hr
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.