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- Question
- Two trains are moving in the same direction with speeds of 15 km/h and 21km/h respectively. What is the speed of trains in respect of each other?
Options- A. 26 km/h
- B. 15 km/h
- C. 6 km/h
- D. 24 km/h
- Correct Answer
- 6 km/h
ExplanationWe know that, if two trains are running in the same direction, then relative speed is equal to the difference of the speeds of both the trains.
? Required relative speed = 21 - 15 = 6 km/h - 1. Two train are moving in opposite direction with speed of 6 m/s and 12 m/s, respectively. Find their relative speed.?
Options- A. 18 m/s
- B. 15 m/s
- C. 20 m/s
- D. 6 m/s Discuss
- 2. A train crossed a platform in 43 s. The length of the train is 170 m. What is the Speed of the train?
Options- A. 233 km/h
- B. 243 km/h
- C. 265 km/h
- D. Con not be determined Discuss
- 3. A 240 m long train crosses a platform of equal length in 27 s. What is the speed of the train in km/h?
Options- A. 48
- B. 60
- C. 56
- D. 64 Discuss
- 4. A 220 m long train passes a signal post in 12 s. Find the speed f the train.?
Options- A. 72 km/h
- B. 60 km/h
- C. 66 km/h
- D. 69 km/h Discuss
- 5. A train covers 90 m in passing a standing man. Find the length of the train.
Options- A. 20 m
- B. 87 m
- C. 71 m
- D. 90 m Discuss
- 6. The relative speed of a train in respect of a car is 90 km/h when train and car are moving opposite to each other. Find the actual speed of train . If car is moving with a speed of 15 km/h.?
Options- A. 80 km/h
- B. 105 km/h
- C. 75 km/h
- D. 100 km/h Discuss
- 7. What is the time taken by a train running at 18 km/h to cross a man standing on a platform, length of the train is 120 m?
Options- A. 22 s
- B. 44 s
- C. 12 s
- D. 24 s Discuss
- 8. A train takes 5 seconds to pass an electric pole. If the length of the train is 120 meters, the time taken by it to cross a railway platform 180 meter long, is?
Options- A. 121/2seconds
- B. 71/2seconds
- C. 61/2 seconds
- D. 31/3seconds Discuss
- 9. A train 120 meters long, crosses a pole in 10 seconds. The speed of the train is?
Options- A. 40 km/hr
- B. 43.2 km/hr
- C. 45 km/hr
- D. None of these Discuss
- 10. The distance between two station A and B is 220 km. A train leaves A toward B at an average speed of 80 km/hr. after half an hour another train leaves B toward A at an average speed at 100 km/hr. the distance of the point of two train meet, from A is?
Options- A. 120 km.
- B. 130 km.
- C. 140 km.
- D. 150 km. Discuss
Problems on Trains
Search Results
Correct Answer: 18 m/s
Explanation:
When two trains are moving in opposite directions then their relative speed is equal to the sum of the speed of both the trains.
? Required relative speed = 6 + 12 = 18 m/s
Correct Answer: Con not be determined
Explanation:
Length of platform is not given. it can not be determined.
Correct Answer: 64
Explanation:
By the formula, speed= Distance/ Time
= (240 + 240)/27 x (18/5)
= 480/27 x 18/5 = 64 km/h
Correct Answer: 66 km/h
Explanation:
We know that,
Speed = Distance/ Time
Speed of the train = 220/12 x (18/5) km/h
Correct Answer: 90 m
Explanation:
We know that, the distance covered by a train in passing a pole or a standing man or a signal post or any other object (of negligible length) is equal to the length of the train.
In this case, train covers 90 m to cross a standing man.
? Length of the train = 90 m
Correct Answer: 100 km/h
Explanation:
Relative speed of train
= Speed of train + Speed of car
? 90 = Speed of train + 15
? Speed of train = 90 - 15 = 75 km/h
Correct Answer: 24 s
Explanation:
Speed of the train = 18 km/h = 18 x 5/18 m/s = 5 m/s
Distance covered = Length of the train = 120 m
? Time taken by the train to cross the man = Distance/Speed
= 120/5 = 24 s
Correct Answer: 121/2seconds
Explanation:
Speed of train = (120/5) = 24 m/sec.
Time takes to cross the platform
= (120 + 180)/24
= 121/2
Correct Answer: 43.2 km/hr
Explanation:
Length of train = 120 m.
Total taken in crossing the pole = 10 seconds.
Speed of the train = length / time
= 120 / 10
= 12 m/s
= 12 x (18/5)
= 43.2 km/hr
Correct Answer: 120 km.
Explanation:
Let the required distance be x km.
Then, ( x/80 ) - ( 220 - x ) / 100 = 1/2
? 5x - 4( 220 - x ) = 200
? 9x = 1080
? x = 120 km
? Required distance = 120 km
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