Distance covered by train in 10 sec = (50 + 100) = 150 m
? Speed = 150/10 m/sec = 15 x (18/5) = 54 km/hr
Distance covered in 2/60 hours = (1 + 1/2) = 3/2 km
Distance covered in 1 hour = (3/2) x (60/2) = 45 km
So, speed of the train = 45 km/hr
Total distance = 70 + 80 = 150 m
Relative speed = 68 + 40 = 108 kmph = 108 x (5/18) = 30 m/s
So time taken = 150 / 30 = 5 seconds.
? Relative speed of the train = 60 + 6 = 66 km/hr
= 66 x 5/18 m/sec = 55/3 m/sec
? Required time = 110 x (3/55) = 6 sec
Distance covered = 110 + 240 = 350 m
Speed = 60 km/ph = 60 x (5/18) m/s = 50/3 m/sec.
Time = distance / speed = 350 x 3 / 50 = 21 sec.
Speed of train = distance covered / time.
= (50 + 100) / 10
= 15 m/sec.
We know that, the distance covered by a train in passing a pole or a standing man or a signal post or any other object (of negligible length) is equal to the length of the train.
In this case, train covers 90 m to cross a standing man.
? Length of the train = 90 m
We know that,
Speed = Distance/ Time
Speed of the train = 220/12 x (18/5) km/h
By the formula, speed= Distance/ Time
= (240 + 240)/27 x (18/5)
= 480/27 x 18/5 = 64 km/h
Length of platform is not given. it can not be determined.
When two trains are moving in opposite directions then their relative speed is equal to the sum of the speed of both the trains.
? Required relative speed = 6 + 12 = 18 m/s
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