Distance covered = 110 + 240 = 350 m
Speed = 60 km/ph = 60 x (5/18) m/s = 50/3 m/sec.
Time = distance / speed = 350 x 3 / 50 = 21 sec.
Speed of train = distance covered / time.
= (50 + 100) / 10
= 15 m/sec.
Required speed = (240 + 120) / 24 = 15 m/sec
= 15 x (18/5) km/hr = 54 km/hr
Time = distance / speed
=110 / {60 x 18/5} = 6.6 sec.
Distance covered = 550 meter. = 0.55 km
Speed of the train = 55 km/hr
So time taken = 0.55 / 55 =1/100 hr = (60 x 60 )/100 sec = 36 sec
Distance traveled = length of the train = 135 m
Speed of the train = 54 Km/hr = 54 x 5/18 = 15 m/s.
Time taken by train = 135 / 15 sec. = 9 sec.
? Relative speed of the train = 60 + 6 = 66 km/hr
= 66 x 5/18 m/sec = 55/3 m/sec
? Required time = 110 x (3/55) = 6 sec
Total distance = 70 + 80 = 150 m
Relative speed = 68 + 40 = 108 kmph = 108 x (5/18) = 30 m/s
So time taken = 150 / 30 = 5 seconds.
Distance covered in 2/60 hours = (1 + 1/2) = 3/2 km
Distance covered in 1 hour = (3/2) x (60/2) = 45 km
So, speed of the train = 45 km/hr
Distance covered by train in 10 sec = (50 + 100) = 150 m
? Speed = 150/10 m/sec = 15 x (18/5) = 54 km/hr
We know that, the distance covered by a train in passing a pole or a standing man or a signal post or any other object (of negligible length) is equal to the length of the train.
In this case, train covers 90 m to cross a standing man.
? Length of the train = 90 m
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