Distance traveled = length of the train = 135 m
Speed of the train = 54 Km/hr = 54 x 5/18 = 15 m/s.
Time taken by train = 135 / 15 sec. = 9 sec.
Speed of the train = 36 km/hr = 36 x (5/18) = 10 m/sec
? Required time = 110/10 = 11 sec
Since the sum of the length of the train and the length of the engine is needed, so both the lengths must be known.
180 km/hr = 180 x (5/18) = 50 m/sec
16 m/sec = 16 x (18/5) = 57.6 km/hr
? Speed of the train = 50 x (5/18) = 125/9 m/sec
? Time taken by the train to pass the pole = 250 x (9/125) = 18 sec
Distance covered = 550 meter. = 0.55 km
Speed of the train = 55 km/hr
So time taken = 0.55 / 55 =1/100 hr = (60 x 60 )/100 sec = 36 sec
Time = distance / speed
=110 / {60 x 18/5} = 6.6 sec.
Required speed = (240 + 120) / 24 = 15 m/sec
= 15 x (18/5) km/hr = 54 km/hr
Speed of train = distance covered / time.
= (50 + 100) / 10
= 15 m/sec.
Distance covered = 110 + 240 = 350 m
Speed = 60 km/ph = 60 x (5/18) m/s = 50/3 m/sec.
Time = distance / speed = 350 x 3 / 50 = 21 sec.
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