? Speed of the train = 50 x (5/18) = 125/9 m/sec
? Time taken by the train to pass the pole = 250 x (9/125) = 18 sec
? Speed of the train = 60 x (5/18) m/sec = 50/3 m/sec
? Time taken by the train to cross the platform
= Time taken by it to cover (280 + 220) m
= (500 x 3/50) sec = 30 sec
Speed of the train = (36 x 5)/18 = 10 m/sec.
Distance = (Time x Speed ) = (8 x 10 ) = 80 meters
? Length of the train = 80 meters
? Speed = Distance / Time = (300/15)
= 20 m/sec
= (20 x 18) / 5 = 72 km/hr
Relative speed = (25 + 2) = 27 km/hr = 27 x (5/18) m/sec. = 15/2 m/sec.
Time taken by the train to pass the men. = 270 / (15/2) = 36 sec.
Let the required speed be y km/hr.
Then, ( 2 x 64 ) x [ y / (64 + y)] = 56
? 128y = 64 x 56 + 56y
? y= (64 x 56 ) / 72
= 49.77 km/hr.
16 m/sec = 16 x (18/5) = 57.6 km/hr
180 km/hr = 180 x (5/18) = 50 m/sec
Since the sum of the length of the train and the length of the engine is needed, so both the lengths must be known.
Speed of the train = 36 km/hr = 36 x (5/18) = 10 m/sec
? Required time = 110/10 = 11 sec
Distance traveled = length of the train = 135 m
Speed of the train = 54 Km/hr = 54 x 5/18 = 15 m/s.
Time taken by train = 135 / 15 sec. = 9 sec.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.