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- Question
- A car covers a distance from town A to town B at the speed of 58 km/h and covers the distance from town B to town A at the speed of 52 km/ h. What is the Approximate average speed of the car?
Options- A. 55 km/h
- B. 52 km/h
- C. 48 km/h
- D. 60 km/h
- Correct Answer
- 55 km/h
ExplanationWe know that, if two equal distances are covered at two different speeds A and B, then
Average speed = 2AB/(A + B) = (2 x 58 x 52)/(58 + 52)
= 54.8 km/h
= 55 km/h (Approx) - 1. Two cars X and Y starts from two places A and B respectively which are 700 km apart at 9 am. Both the cars run at an average speed of 60 km/h, Car X stops at 10 am and again starts at 11 am, while the other car Y continues to run without stopping. When do the two cars cross each other?
Options- A. 2 : 40 pm
- B. 3 : 20 pm
- C. 4 : 10 pm
- D. 4 : 20 pm Discuss
- 2. Amit start from a point A and walks to another point B and then return from B to A by his car and thus takes a total time of 6 h 45 min. If he had driven both ways in his car, he would have taken 2 h less. How long would it take for him to walk both ways?
Options- A. 7 h 45 min
- B. 8 h 15 min
- C. 8 h 30 min
- D. 8 h 45 min Discuss
- 3. Total time taken by a person in going to a place by walking and returning on cycle is 5 h 45 min. He would have gained 2 h by cycling both ways. The time taken by him to walk both ways, is?
Options- A. 6 h 45 min
- B. 7 h 45 min
- C. 8 h 15 min
- D. 8 h 30 min Discuss
- 4. A person travelled a distance of 50 km in 8 h. He covered a part of the distance on foot at the rate of 4 km/h and a part on a bicycle at the rate of 10 km/h. How much distance did he travel on foot?
Options- A. 10 km
- B. 20 km
- C. 30 km
- D. 40 km Discuss
- 5. Two train of length 250 m and 140 m are running on parallel lines in the same direction at 58 km/h and 32 km/h, respectively. Find the time taken by the slower train to pass the driver of the faster one?
Options- A. 58 s
- B. 54 s
- C. 52 s
- D. 48 s Discuss
- 6. A car reached Raipur from sonagarh in 35 min with an average speed of 69 km/h. If the average speed is increased by 36 km/h, how long will it take to cover the same distance?
Options- A. 24 min
- B. 27 min
- C. 23 min
- D. 29 min Discuss
- 7. A student walks from his house at 2 1/ 2 km/h and reaches his school late by 6 min. Next day, he increase his speed by 1 km/h and reaches 6 min before school time. How far is the school form his house?
Options- A. 5/4 km
- B. 7/4 km
- C. 9/4 km
- D. 11/4 km Discuss
- 8. A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman, chases him. The thief and the policeman run at rate of 10 km/h and 11 km/h, respectively. The distance between them after 6 min will be?
Options- A. 100 m
- B. 180 m
- C. 150 m
- D. 125 m Discuss
- 9. A truck covers a distance of 368 km at a certain speed in 8 h. How much time would a car take at an average speed which is 18 km/h more than that of the speed of the truck to cover a distance which is 16 km more than that travelled by the truck?
Options- A. 7 h
- B. 5 h
- C. 6 h
- D. 8 h Discuss
- 10. Shantanu drives a motorcycle and covers a distance of 715 km at a constant speed.
If the speed of the motorcycle had been 10 km/h more, he would have taken 2 h less to cover the same distance. What is the original speed of the motorcycle?
Options- A. 65 km/h
- B. 55 km/h
- C. 60 km/h
- D. 36 km/h Discuss
Time and Distance problems
Search Results
Correct Answer: 3 : 20 pm
Explanation:
Since, the speed of X and Y are 60 km/h each. The distance between A and B is 700 km. Distance traveled by X upto 11 am is 60 km. Since, X stops at 10 am and distance traveled by up to 11 am is 120 km.
Now, the distance between them = 700 - 180 = 520 km
Now, let they will meet at a distance of x km from X's position.
? Distance traveled by X = x km
and distance traveled by Y = (520 - x) km
? x/60 = (520 - x)/60
? 2x = 520
? x = 260
? T = 260/60 = 41/3 h
Thus, they will cross each other after, 41/3 h after 11 am i.e., at 3 : 20 pm.
Correct Answer: 8 h 45 min
Explanation:
Let w be the time taken in one way by walking and c be the time taken in one way by car.
Now, according to the question,
In first case, w + c = 6 h 45 min
or
2w + 2c = 13 h 30 min ..(i)
In second case, 2c = 4 h 45 min ....(ii)
From Eqs. (i) and (ii), we get
2w + 2c = 13 h 30 min
? 2w + 4h 45 min = 13 h 30 min
? 2w = 13 h 30 min - 4 h 45 min
? 2w = 8 h 45 min
? If he walks both ways, then time taken = 8 h 45 min
Correct Answer: 7 h 45 min
Explanation:
Walking time + Cycling time = 5 h 45 min = 345 min ....(i)
If he had cycled both way he would have gained 2 h (120 min).
? 2 x Cycling time = 345 - 120 = 225 min ...(ii)
Walking time = 2 x 345 - 225 = 690 - 225 = 465 min
Time taken by him to walk both ways = 7 h 45 min
Correct Answer: 20 km
Explanation:
Let T h, he travels on foot.
? 4T + 10(8 - T) = 50
? 80 - 6T = 50
? 6T = 30,
? T = 5 h
? The distance travelled on foot = 4 x 5 = 20 km
Correct Answer: 54 s
Explanation:
Relative speed = (58 - 32) = 26 km/h
= (26 x 5/18) m/s = 65/9 m/s
Time taken to cross each other = (250 + 140)/(65/9)
= (390 x 9)/65 = 54 s
Correct Answer: 23 min
Explanation:
Distance between Sonagarh and Raipur = Average speed x time
= 69 x (35/60) km = 161/4 km
New speed = (69 + 36) km/h = 105 km/h
? Required time = Distance/speed
= 161/(4 x 105) h
= (161 x 60)/(4 x 105) min
= 23 min
Correct Answer: 7/4 km
Explanation:
Let the required distance = L
According to the question,
L/(5/2) - L/(7/2) = 12/60 (difference between two times = 6 + 6 =12 min)
? 2L/5 - 2L/7 = 1/5
? 14L - 10L = 7
? 4L = 7
? L = 7/4 km
Correct Answer: 100 m
Explanation:
Relative speed of policeman with respect to thief = ( 11 - 10 ) = 1 km/h.
Now, relative distance covered by policeman in 6 min = Speed x Time
= (1 x 6)/60 = 1/10 km = 100 m
The distance between the policeman and thief after 6 min = (200 - 100) = 100 m
Correct Answer: 6 h
Explanation:
Speed of truck = Distance/time = 368/8 = 46 km/h
Now, speed of car = (speed of truck + 18) km/h = (46 + 18) = 64 km/h and
Distance travelled by car = 368 + 16 = 384 km
? Time taken by car = Distance/Speed = 384/64 h = 6 h
Correct Answer: 55 km/h
Explanation:
Let the constant speed = V
According to the question,
715/V - 715/(V + 10) = 2
? 1/V - 1/(V + 10) = 2/715
? [(V + 10) - V] / [V(V + 10)] = 2/715
? V2 + 10V = 10 x 715/2
? V2 + 10V - 3575 = 0
? V2 + 65V - 55V - 3575 = 0
? V(V + 65) - 55(V + 65) = 0
? (V - 55) (V + 65) = 0
? V = 55 or V = - 65
Ignoring the negative value, we get V = 55
? Original speed of the motorcycle = 55 km/h
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