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Home Aptitude Time and Distance See What Others Are Saying!
  • Question
  • A man goes to the fair in Funcity with his son and faithful dog. Unfortunately man misses his son which he realises 20 minutes later. The son comes back towards his home at the speed of 20 m/min and man follows him at 40 m/min. The dog runs to the son (child) and comes back to the man (father) to show him the direction of his son. It keeps moving to and fro at 60 m/min between son and father, till the man meets the son. what is the distance travelled by the dog in the direction of the son?


  • Options
  • A. 800 m
  • B. 1675 m
  • C. 848 m
  • D. 1000 m

  • Correct Answer
  • 1000 m 

    Explanation

    In 20 minutes the difference between man and his son = 20 x 20 = 400 m
    Distance travelled by dog when he goes towards son = (400/40) x 60 = 600 m and time required is 10 minutes
    In 10 minutes the remaining difference between man and son = 400 - (20 x 10) = 200 m

    Note: Relative speed of dog with child is 40 km/h and the same with man is 100 km/h.
    Time taken by dog to meet the man = 200/100 = 2 min
    In 2 minute the remaining distance between child and man = 200 - ( 2 x 20) = 160 m
    Now, the time taken by dog to meet the child again = 160/40 = 4 min
    In 4 minutes he covers 4 x 60 = 240 m distance while going towards the son.
    In 4 minute the remaining distance between man and child = 160 - (4 x 20) = 80 m
    Time required by dog to meet man once again = 80/100 = 0.8 min
    In 0.8 min remaining distance between man and child = 80 - (0.8 x 20) = 64 min
    Now, time taken by dog to meet the child again = (64/40) x (8/5) min
    ? Distance travelled by dog = (8/5) x 60 = 96 m
    Thus, we can observe that every next time dog just go 2/5th of previous distance to meet the child in the direction of child.
    So, we can calculate the total distance covered by dog in the direction of child with the help of GP formula.
    Here, first term (a) = 600 and common ratio (r) = 2/5
    Sum of the infinite GP = a/(1 - r)
    = 600/(1 - 2/5) = (600 x 5)/3 = 1000 m


  • More questions

    • 1. 
      The age of a father 10 years ago was thrice the age his son. Ten years later, the father's age will be twice that of his son. The ratio of their present ages is?

    • Options
    • A. 8 : 5
    • B. 7 : 3
    • C. 5 : 2
    • D. 9 : 5
    • Discuss
    • 2. 
      The ratio of Laxmi's age of the age of her mother is 3 : 11. the difference of their ages is 24 years. The ratio of their ages after 3 yeras will be?

    • Options
    • A. 1 : 3
    • B. 2 : 3
    • C. 3 :5
    • D. None of these
    • Discuss
    • 3. 
      The total ages of A, B and C at present is 90 years. Ten years ago the ratio of their ages was 1 : 2 : 3. Then the present age of B is ....?

    • Options
    • A. 30 years
    • B. 20 years
    • C. 40 years
    • D. None of these
    • Discuss
    • 4. 
      A father's age is four times as much as the sum of the ages of his three children but 6 years hence his age will be only double the sum of their ages. Then the age of the father is?

    • Options
    • A. 30 years
    • B. 40 years
    • C. 60 years
    • D. 45 years
    • Discuss
    • 5. 
      Present age of Rahul is 8 years less then Ritu's present age. If three years ago Ritu's age was x, which of the following represents Rahul's present age?

    • Options
    • A. x + 3
    • B. x - 5
    • C. x - 3 + 8
    • D. x + 3 + 8
    • Discuss
    • 6. 
      The ratio in the ages of A and B, 1 year ago was 3 : 4. While it will be 5 : 6 after 1 year. What is the present age of B?

    • Options
    • A. 8 years
    • B. 4 years
    • C. 6 years
    • D. None of these
    • Discuss
    • 7. 
      If A son is younger then his father by 25 years and the father was 45 years old,4 years ago. What will be the total age of the father and son after 5 years?

    • Options
    • A. 82 years
    • B. 88 years
    • C. 83 years
    • D. 78 years
    • Discuss
    • 8. 
      The ratio of the ages of Ram and Rahim 10 yr ago was 1 : 3 . The ratio of their ages five years hence will be 2 : 3. Then, the ratio of their present ages is?

    • Options
    • A. 1 : 2
    • B. 3 : 5
    • C. 3 : 4
    • D. 2 : 5
    • Discuss
    • 9. 
      The present age of Ravi's father is four times Ravi's present age.Five years back, Ravi's father was seven times as old as Ravi was at that time. What is the present age of Ravi's father?

    • Options
    • A. 84 yr
    • B. 70 yr
    • C. 40 yr
    • D. 35 yr
    • Discuss
    • 10. 
      If the two digits of the age of Mr. Manoj are reversed then the new age so obtained is the age of his wife. 1/11 of the sum of their ages is equal to the difference between their ages. If Mr. Manoj is elder than his wife then find the difference their ages?

    • Options
    • A. Cannot be determined
    • B. 10 years
    • C. 8 years
    • D. 9 years
    • Discuss


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