In 20 minutes the difference between man and his son = 20 x 20 = 400 m
Distance travelled by dog when he goes towards son = (400/40) x 60 = 600 m and time required is 10 minutes
In 10 minutes the remaining difference between man and son = 400 - (20 x 10) = 200 m
Note: Relative speed of dog with child is 40 km/h and the same with man is 100 km/h.
Time taken by dog to meet the man = 200/100 = 2 min
In 2 minute the remaining distance between child and man = 200 - ( 2 x 20) = 160 m
Now, the time taken by dog to meet the child again = 160/40 = 4 min
In 4 minutes he covers 4 x 60 = 240 m distance while going towards the son.
In 4 minute the remaining distance between man and child = 160 - (4 x 20) = 80 m
Time required by dog to meet man once again = 80/100 = 0.8 min
In 0.8 min remaining distance between man and child = 80 - (0.8 x 20) = 64 min
Now, time taken by dog to meet the child again = (64/40) x (8/5) min
? Distance travelled by dog = (8/5) x 60 = 96 m
Thus, we can observe that every next time dog just go 2/5th of previous distance to meet the child in the direction of child.
So, we can calculate the total distance covered by dog in the direction of child with the help of GP formula.
Here, first term (a) = 600 and common ratio (r) = 2/5
Sum of the infinite GP = a/(1 - r)
= 600/(1 - 2/5) = (600 x 5)/3 = 1000 m
Let son's age 10 years ago be x years.
? father's age 10 years ago = 3x years
? 3x + 20 = 2(x + 20)
? x = 20
? Ratio of their present ages = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3
Let the ages of Laxmi and her mother be 11x and 3x respectively.
From question, 11x - 3x = 24
? x = 3
? Ratio of their ages after 3 years = ( 3x + 3) : (11x + 3 )
= 12: 36 = 1 : 3
Let the respective ages of A, B and C, ten years ago be x, 2x and 3x years.
? (x + 10) + (2x + 10) + ( 3x + 10) = 90
? 6x = 60
? x = 10
? B's present age = 2x + 10 = 30 years
Let father's age be x years and the sum of ages of children be y years.
? x = 4 y ....(i)
Also (x + 6) = 2(y + 6 + 6 + 6) ....(ii) [6 is added thrice for three children ]
Solving (i) and (ii)
x = 60 years, and y = 15 years.
Let the Rahul's present age is 'A' years. Then Ritu's present age is (A + 8)
Now, according to the question,
(A + 8) - 3 = x
? A = (x - 5) years
Let the present age of A and B be x and y years respectively
From 1st condition
(x - 1) / (y -1) = 3/4
? 4x - 4 = 3y - 3
? 4x - 3y = 1 ... (i)
From 2nd condition,
(x + 1) / (y + 1) = 5/6
? 6x + 6 = 5y + 5
? 6x - 5y = -1 ...(ii)
Multiplying equation (i) by 3 and equation (ii) by 2 and subtract
y = 5
? Present age of B = 5 years
Let the present age of father be x years, Then the present age of son = (x - 25) years .
According to to question,
x - 4 = 45
? x = 45 + 4
? x = 49
? Age of son = 49 - 25 = 24 years
? Age of son after five years = 24 + 5 = 29 years
? Age of father after five years = 49 + 5= 54 years
Total age of both = 29 + 54= 83 years
Let 10 yr ago, ages of Ram and Rahim were k yr and 3k yr, respectively.
Then, present age of Ram = (k + 10)
and present age of Rahim = (3k + 10)
According to the question, (k + 10 + 5) / (3k + 10 + 5) = 2/3
? 3k + 45 = 6k + 30
? 3k = 15
? k = 5
Hence, required ratio = (5 + 10) / (3 x 5 + 10)
= 15/25
= 3 : 5
Let present age of Ravi be k.
Then, Present age of Ravi's father = 4k.
Now, 5 yr ago,
Ravi's father's age = 7 x Ravi's age
? 4k - 5 = 7(k - 5)
? 4k - 5 = 7k - 35
? 3k = 30
? k = 10
? Ravi's present age = k = 10 yr
? Ravi's father's present age = 4k
= 4 x 10 = 40 yr
Let the age of Mr Manoj be (10y + y) yrs.
? His wife's age = (10y + x ) years
Then, ((10x + y + 10y + x) / 11 = 10x + y -10y-x
? x + y = 9x - 9y
? 8x = 10y
? x/y = 5/4
? x = 5 and y =4 (because any other multiple of 5 will make x of two digits).
? Diff. = (10x + y) - (10y - x)
= 9x - 9y
= 9(x-y)
= 9(5-4)
= 9 yrs.
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