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- Question
- If a train run at 40 km/hr it reaches its destination late by 11 min but if it run at 50 km/hr it is late by 5 min only. The correct time for the train to cover at journey is?
Options- A. 13 min.
- B. 15 min.
- C. 21 min.
- D. 19 min.
- Correct Answer
- 19 min.
ExplanationLet the required time = T min.
Then, distance covered in T + 11 min at 40 km/hr = distance covered in T + 5 min at 50 km/hr.
? 40 ( T + 11 ) / 60 = 50 (T + 5 ) / 60
? T = 19 min. - 1. A man travel 35 km partly at 4 km/hr if he covers former distance at 5 km/hr and later distance at 4 km/hr he could cover 2 km. more in the same time. The time taken to cover the whole distance at original rate is?
Options- A. 9 hours
- B. 7 hours
- C. 4 1/2 hours
- D. 8 hours Discuss
- 2. The ratio between the rates of travelling of A and B is 2:3 and therefore A takes 10 min. more than the time taken by B to reach a destination, if A had walked at double the speed, he would have covered the distance in?
Options- A. 30 min
- B. 25 min
- C. 15 min
- D. 20 Min Discuss
- 3. A bullock cart has to cover a distance of 80 km. in 10 hours. If it cover half of journey in 3/5 th time, what should be its speed to cover the remaining distance in time left?
Options- A. 8 km/hr.
- B. 20 km/hr.
- C. 6.4 km/hr.
- D. 10 km/hr. Discuss
- 4. Two cyclists A and B start from the same place at the same time. One going toward north at 18 km/hr. and other going toward south at 20 km/hr. What time will they take to be 95 km. apart?
Options- A. 4 hrs. 30 min.
- B. 4 hrs. 45 min.
- C. 5 hrs.16 min.
- D. 2hrs. 30 min Discuss
- 5. Suresh traveled 1200 km by air which formed (2/5) of his trip. One-third of the whole trip he traveled by car And the rest of the journey he performed by train. The distance traveled by train was?
Options- A. 1600 km.
- B. 800 km.
- C. 1800 km.
- D. 400 km. Discuss
- 6. A train Meerut at 6 a.m. and reaches Delhi at 10 a.m. another train leaves Delhi at 8 a.m. and reaches Meerut at 11:30 a.m. at what time do trains cross one another?
Options- A. 9.26 a.m.
- B. 9 a.m.
- C. 8:36 a.m.
- D. 8:56 a.m. Discuss
- 7. A train leaves Delhi at 5 a.m. and reaches Kanpur at 10 a.m. another train leaves Kanpur at 7 a.m. and reaches Delhi at 2 p.m. at what time do the two trains meet?
Options- A. 8:45 a.m.
- B. 3:45 p.m.
- C. 6:45 a.m.
- D. data inadequate Discuss
- 8. A start from P walk to Q a distance of 51.75 kilometer at the rate of 3.75 km an hour. An hour latter B starts from Q for P and walk at the rate of 4.25 km an hour. When and where will A meet B?
Options- A. 26.25 km. from Q
- B. 25.50 km. from Q
- C. 25.30km. from P
- D. can't be determined Discuss
- 9. Two boys begin together to write out a booklet containing 817 lines. The first boy start with first line, writing at rate of 200 lines an hour and the second boys start with a last line. He writes line 817 and so on backwards proceeding at the rate of 150 lines an hour. An what line will they meet?
Options- A. 466th
- B. 465th
- C. 467th
- D. 468th Discuss
- 10. Two car A and B are running toward each other from two different place 88 km apart. If the ratio of the speed of the car A and B is 5:6 and the speed of the car B is 90 km per hour, after how long will the two meet each other?
Options- A. 26 min.
- B. 24 min.
- C. 32 min.
- D. 36 min. Discuss
Time and Distance problems
Search Results
Correct Answer: 8 hours
Explanation:
Suppose the man covers first distance in x hrs and second distance in y hrs.
Then, 4x + 5y = 35 and 5x + 4y = 37
Solving these equations, we get
x = 5 and y = 3
? Total time taken = 5 + 3 hrs.
= 8 hrs.
Correct Answer: 15 min
Explanation:
Ratio of times taken by A and B = 1/2 : 1/3
Suppose B takes Tb min. Then A takes (Tb + 10) min.
? (Tb + 10 ) : Tb = 1/2: 1/3
? (Tb + 10)/Tb = 3 / 2
? 2Tb + 20 = 3Tb
? Tb = 20
? Time taken by A = 20 +10
= 30 minute
If A had walked at double speed
Req . time = 30/2
=15 minute
Correct Answer: 10 km/hr.
Explanation:
Distance left = (1/2 x 80 ) km. = 40km.
Time left - [(1-3/5) x 10 ] hrs.
= 4 hours
Required speed = (40 / 4 ) km/hr
= 10 km/hr.
Correct Answer: 2hrs. 30 min
Explanation:
Relative velocity = u + v = 18 + 20 = 38 km
They are 38 km. apart in 1 hr.
? They will be 95 km. apart in ( 95 / 38) hrs.
= 2 hrs . 30 min
Correct Answer: 800 km.
Explanation:
Let the total distance be y km.
Then, 2y / 5 = 1200
? y = (1200 x 5) /2 = 3000 km.
Distance traveled by car
= (1/3 X 3000) = 1000 km.
Distance traveled by train
= [3000- (1200 + 1000) ] km.
= 800 km.
Correct Answer: 8:56 a.m.
Explanation:
Let the distance between Meerut and Delhi be y km.
Average speed of the train leaving Meerut = y/4 km/hr.
Average speed of the train leaving Delhi = 2y/7 km/hr.
suppose they meet x hrs. after 6 a.m
then, xy/4 + 2y (x-2)/7 = y
? x/4 + 2x-4/7 = 1
? 15x = 44
? x = 44/15 = 2 hrs. 56 min
So, the train meet at 8:56 a.m
Correct Answer: 8:45 a.m.
Explanation:
Let the distance between Delhi and Kanpur be y km .
Suppose the train leaving from Delhi is A and the train leaving from Kanpur B
A's speed = y/ (10 a.m - 5 a.m) = y/5 km/hr.
B's Speed = y/ (2 p.m - 7 a.m) = y/7 km/hr.
Since B starts two hours later than A, the distance already covered by A at the start of B = 2y/5 km.
Remaining distance = y- 2y/5 = 3y/5 km.
Relative speed of approach of two trains = (y/5 + y/7)
= 12y/35 km/hr.
Time taken to cover the remaining distance by both trains = (3y / 5) / (12y / 35)
= (3/5) x (35/12) = 7/4 hrs.
= 1 hr. 45 min.
? The two train will meet at (7 a.m + 1hr.45 min)
= 8.45 a.m
Correct Answer: 25.30km. from P
Explanation:
A has already gone 3.75 km when B starts of the remaining 48 km.
A walks 3.75 km and B walks 4.25 km in one hour in opposite direction i.e., they together pass over (3.75 + 4.25) = 8 km. in hour.
Therefore , 48 km. are passed over in 48/8= 6 hours.
? A meets B in 6 hours after B started and, therefore, they meet at a distance of (4.25 X 6 ) = 25.5km. from Q.
Correct Answer: 467th
Explanation:
Let the two meet at the Nth line
From the question
Nth/200 = (817 - Nth)/150
? 3Nth = 4(817-Nth)
? Nth = (4 x 817) / 7
? Nth = 466.85
So, they will meet at the 467th line
Correct Answer: 32 min.
Explanation:
Speed of the car A = (5 / 6) x 90
= 75 km/hr.
? Required time = [ 88 / (90 +75)] x 60
= 32 minutes
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